Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)

Pipes and Cistern

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

1	13	hours
	17

2	8	hours
	11

3	9	hours
	17

4	1	hours
	2

Answer: Option

Explanation:

Net part filled in 1 hour		1	+	1	-	1		=	17	.
		5		6		12			60

The tank will be full in	60	hours i.e., 3	9	hours.
	17		17

Discussion:

57 comments Page 3 of 6.

Anish Gupta said: 8 years ago

@Neha

Just forget that LCM part if 17tank is filled in 60hours the how many tank will be filled in 1 hour.

17tank = 60hours
1tank = x,
17 * x = 60 * 1tank = x = 60/17.

(1)

Rohit said: 8 years ago

Thanks @Manasa.

Ramya said: 9 years ago

Thank you @Manasa.

Jerry said: 9 years ago

Thank you @Manasa.

Neha said: 9 years ago

In 17/60 60 is LCM of numbers but how 70 comes?

Shruthi g.r said: 9 years ago

Can you please once again clear how it comes 60/17 in hours 3 * 9/17?

Rahul Namdev said: 9 years ago

@Kaveri.

Pipe A =1/5 hrs & B=1/6 hrs, & C=/12 hrs.

LCM of 5, 6 , 12 = 60.
Units or liter (whatever) of :
A = 5 (hours)/60(units) = 12 units.
B = 6 (hours)/60(units) = 10 units.
C = 12 (hours)/60(units) = 5 units.

Now, add A + B(inlet pipe) - C (outlet pipe)/ 60.
--> 22 - 5/60.
---> 17/60.

(2)

Rakesh said: 9 years ago

@Alka your answer is best, so thanks.

Sandeep said: 10 years ago

Can you please explain it clearly that how we get 3*9/17?

Sushmitha said: 10 years ago

17)60(3
51

= 60-51 = 9.

Then q*(r/d).

i.e 3*9/17.

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