Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
Answer: Option
Explanation:
| Net part filled in 1 hour |  |
1 | + | 1 | - | 1 |  |
= | 17 | . |
| 5 | 6 | 12 | 60 |
 The tank will be full in |
60 | hours i.e., 3 | 9 | hours. |
| 17 | 17 |
Discussion:
57 comments Page 3 of 6.
Jerry said:
9 years ago
Thank you @Manasa.
Ramya said:
9 years ago
Thank you @Manasa.
Rohit said:
9 years ago
Thanks @Manasa.
Mahesh said:
9 years ago
How the 17 came? Please explain me.
Lavanya said:
7 years ago
Thanks all.
Brijesh said:
8 years ago
How option C is right?
How comes 60/17?
How comes 60/17?
Naushad said:
8 years ago
Dear Sir,
I think the pipes that filling the tank operates under constant pressure. So the flow rate is constant. But the pipe that is draining is operating under varying head, ie. Under varying pressure. So the draining of tank is not uniform, but proportional to the square root of the head. Hence the problem can't be solved using simple mathematics. For centuries we put it in wrong way.
I think the pipes that filling the tank operates under constant pressure. So the flow rate is constant. But the pipe that is draining is operating under varying head, ie. Under varying pressure. So the draining of tank is not uniform, but proportional to the square root of the head. Hence the problem can't be solved using simple mathematics. For centuries we put it in wrong way.
Amudha said:
8 years ago
How it will come 17/60 to 60/17?
Rupa said:
7 years ago
@Sekhar.
17*3+9/60 = 60/17.
17*3+9/60 = 60/17.
Kavi said:
8 years ago
@Neha how?
(51/180)dividing numerator &denominator by 2.
= (17/60).
(51/180)dividing numerator &denominator by 2.
= (17/60).
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