Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
Answer: Option
Explanation:
| Net part filled in 1 hour |  |
1 | + | 1 | - | 1 |  |
= | 17 | . |
| 5 | 6 | 12 | 60 |
 The tank will be full in |
60 | hours i.e., 3 | 9 | hours. |
| 17 | 17 |
Discussion:
57 comments Page 2 of 6.
Subiksha said:
8 years ago
I can't understand this. Anyone explain me clearly?
(1)
Ajmal said:
1 decade ago
How 60/17 can write as 3*9/17?
(1)
Anish Gupta said:
9 years ago
@Neha
Just forget that LCM part if 17tank is filled in 60hours the how many tank will be filled in 1 hour.
17tank = 60hours
1tank = x,
17 * x = 60 * 1tank = x = 60/17.
Just forget that LCM part if 17tank is filled in 60hours the how many tank will be filled in 1 hour.
17tank = 60hours
1tank = x,
17 * x = 60 * 1tank = x = 60/17.
(1)
Ragavi said:
7 years ago
How to calculate it when the time is in minutes (intsead of hrs)? Please tell me.
(1)
Preeti said:
1 decade ago
Thanks Manasa. I got it clearly.
(1)
Sireeshadevi koppisetti said:
6 years ago
Thanks @Subrat Kumar Dhani.
(1)
Marion said:
5 years ago
How does 60/17 become 39/17? Explain me.
(1)
Neha said:
1 decade ago
(1/5 + 1/6 - 1/12) = (6+5/30 - 1/12)
= (11/30 -1/12)
= (132-30/360)
= (102/360)dividing numerator &denominator by 2
= (51/180)dividing numerator &denominator by 2
= (17/60)
= (11/30 -1/12)
= (132-30/360)
= (102/360)dividing numerator &denominator by 2
= (51/180)dividing numerator &denominator by 2
= (17/60)
(1)
Prabhat said:
9 years ago
Just take it by formula.
5 * 6 * 12/6 * 12+ 5 * 12-5 * 6 = 60/17.
5 * 6 * 12/6 * 12+ 5 * 12-5 * 6 = 60/17.
Neha said:
10 years ago
In 17/60 60 is LCM of numbers but how 70 comes?
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