Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
1 13 hours
17
2 8 hours
11
3 9 hours
17
4 1 hours
2
Answer: Option
Explanation:

Net part filled in 1 hour 1 + 1 - 1 = 17 .
5 6 12 60

The tank will be full in 60 hours i.e., 3 9 hours.
17 17

Discussion:
57 comments Page 2 of 6.

Anish Gupta said:   8 years ago
@Neha

Just forget that LCM part if 17tank is filled in 60hours the how many tank will be filled in 1 hour.

17tank = 60hours
1tank = x,
17 * x = 60 * 1tank = x = 60/17.
(1)

Ragavi said:   6 years ago
How to calculate it when the time is in minutes (intsead of hrs)? Please tell me.
(1)

Sireeshadevi koppisetti said:   5 years ago
Thanks @Subrat Kumar Dhani.
(1)

Akshay kenjila said:   4 years ago
@Manasa.

Soperb explainations. Thank you.
(1)

Neha said:   1 decade ago
(1/5 + 1/6 - 1/12) = (6+5/30 - 1/12)
= (11/30 -1/12)
= (132-30/360)
= (102/360)dividing numerator &denominator by 2
= (51/180)dividing numerator &denominator by 2
= (17/60)
(1)

Marion said:   5 years ago
How does 60/17 become 39/17? Explain me.
(1)

Naren said:   4 years ago
Thanks for explaining @Manasa.
(1)

Preeti said:   1 decade ago
Thanks Manasa. I got it clearly.
(1)

Brijesh said:   7 years ago
How option C is right?

How comes 60/17?

Neha said:   9 years ago
In 17/60 60 is LCM of numbers but how 70 comes?


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