Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
1 13 hours
17
2 8 hours
11
3 9 hours
17
4 1 hours
2
Answer: Option
Explanation:

Net part filled in 1 hour 1 + 1 - 1 = 17 .
5 6 12 60

The tank will be full in 60 hours i.e., 3 9 hours.
17 17

Discussion:
57 comments Page 6 of 6.

Anita sahoo said:   10 years ago
1/5+1/6-1/12=17/60.

How it possible?

1/5+1/6-1/12=-1/20.

Why not? Please explain.

Anita sahoo said:   10 years ago
@Subrat please tell me how C is 5?

Bijayalaxmi said:   10 years ago
Formula: xyz/yz+xz-xy.

Pranav Kumar said:   10 years ago
I didn't understand this problem and can some one make it clear.

Sushmitha said:   10 years ago
17)60(3
51

= 60-51 = 9.

Then q*(r/d).

i.e 3*9/17.

Ang said:   1 decade ago
Why we didnt take ( 1/12 - (1/5+1/6) ). Here 12 is greater right?

Rakesh said:   9 years ago
@Alka your answer is best, so thanks.


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