Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
1 13 hours
17
2 8 hours
11
3 9 hours
17
4 1 hours
2
Answer: Option
Explanation:

Net part filled in 1 hour 1 + 1 - 1 = 17 .
5 6 12 60

The tank will be full in 60 hours i.e., 3 9 hours.
17 17

Discussion:
57 comments Page 3 of 6.

Nelson said:   1 decade ago
@Sameera, the tank will be filled as you can see the rate of filling is more than the rate of emptying. If the tank can't be filled, then the math would have told us so.

Aryan kanti said:   1 decade ago
How do we find the time taken?

Anita sahoo said:   10 years ago
1/5+1/6-1/12=17/60.

How it possible?

1/5+1/6-1/12=-1/20.

Why not? Please explain.

Anita sahoo said:   10 years ago
@Subrat please tell me how C is 5?

Bijayalaxmi said:   10 years ago
Formula: xyz/yz+xz-xy.

Pranav Kumar said:   10 years ago
I didn't understand this problem and can some one make it clear.

Ajmal said:   10 years ago
How 60/17 can write as 3*9/17?
(1)

Sushmitha said:   10 years ago
17)60(3
51

= 60-51 = 9.

Then q*(r/d).

i.e 3*9/17.

Sandeep said:   10 years ago
Can you please explain it clearly that how we get 3*9/17?

Rakesh said:   9 years ago
@Alka your answer is best, so thanks.


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