Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
Answer: Option
Explanation:
| Net part filled in 1 hour |  |
1 | + | 1 | - | 1 |  |
= | 17 | . |
| 5 | 6 | 12 | 60 |
 The tank will be full in |
60 | hours i.e., 3 | 9 | hours. |
| 17 | 17 |
Discussion:
57 comments Page 2 of 6.
Neha said:
1 decade ago
(1/5 + 1/6 - 1/12) = (6+5/30 - 1/12)
= (11/30 -1/12)
= (132-30/360)
= (102/360)dividing numerator &denominator by 2
= (51/180)dividing numerator &denominator by 2
= (17/60)
= (11/30 -1/12)
= (132-30/360)
= (102/360)dividing numerator &denominator by 2
= (51/180)dividing numerator &denominator by 2
= (17/60)
(1)
Deepi said:
1 decade ago
Hi guys use this concepts to find the solution in easily
Concept 1:
A fill tank in x hrs and B fill in Y hrs and C in z hrs means together fill=?
A&B=X*y/x+y
let that A&B ans as p
then A,B&C=p*z/p+z
Concept 2:
A fill tank in x hrs and B empty in Y hrs then both together work how much time is to empty=?
=x*y/y-x
Concept 1:
A fill tank in x hrs and B fill in Y hrs and C in z hrs means together fill=?
A&B=X*y/x+y
let that A&B ans as p
then A,B&C=p*z/p+z
Concept 2:
A fill tank in x hrs and B empty in Y hrs then both together work how much time is to empty=?
=x*y/y-x
Rav said:
1 decade ago
Will it work in every case ?
Divya said:
1 decade ago
Thanks manasa.
Mageswari said:
1 decade ago
Thanks manasa your explanation is clear cut.
Rohit said:
1 decade ago
Thanks neha.
Kiran said:
1 decade ago
@kaveri
1/5+1/6+-1/12=
L.C.M of 5,6,12=60
So 1/5+1/6-1/12
12+10-5
--------------= 17
60 --------
60
1/5+1/6+-1/12=
L.C.M of 5,6,12=60
So 1/5+1/6-1/12
12+10-5
--------------= 17
60 --------
60
Alka said:
1 decade ago
@Happy.
First of all take L.C.M of 5, 6, &12. Then divide this L.C.M with every numerator & multiply that value with denominator of same.
First of all take L.C.M of 5, 6, &12. Then divide this L.C.M with every numerator & multiply that value with denominator of same.
SUBRAT KUMAR DHANI said:
1 decade ago
A PIPE - 5HRS.
B PIPE- 6HRS.
C PIPE - 12HRS TO EMPTY IN TANK, SO THAT,
A-5 B-6 C-12 (TOTAL L.C.M 60 UNIT TANK CAPACITY).
A-12UNIT, B-10UNIT ,C-5UNIT.
TOGETHER(A+B)-EMPTY(C) = 12+10-5 = 17.
TOTAL UNIT 60/17 = 3.52
B PIPE- 6HRS.
C PIPE - 12HRS TO EMPTY IN TANK, SO THAT,
A-5 B-6 C-12 (TOTAL L.C.M 60 UNIT TANK CAPACITY).
A-12UNIT, B-10UNIT ,C-5UNIT.
TOGETHER(A+B)-EMPTY(C) = 12+10-5 = 17.
TOTAL UNIT 60/17 = 3.52
(4)
Sameera said:
1 decade ago
Thanks manasa but I can't understand one point ie;c is used for emptying of tank & when a&b are used to filling of water so when we use the 3 pipes simultaneously then at any time or at any point the will not be FILL so how can we conclude with a simple answer.
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