Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
1 13 hours
17
2 8 hours
11
3 9 hours
17
4 1 hours
2
Answer: Option
Explanation:

Net part filled in 1 hour 1 + 1 - 1 = 17 .
5 6 12 60

The tank will be full in 60 hours i.e., 3 9 hours.
17 17

Discussion:
57 comments Page 6 of 6.

Marion said:   5 years ago
How does 60/17 become 39/17? Explain me.
(1)

BISWANATH TRIPATHY said:   4 years ago
How it is possible? Explain, please.
(2)

Naren said:   4 years ago
Thanks for explaining @Manasa.
(1)

Akshay kenjila said:   4 years ago
@Manasa.

Soperb explainations. Thank you.
(1)

Sanjiv said:   3 years ago
Superb explanation. Thanks @Manasa.
(5)

Madhumita said:   1 year ago
First take a, b, c = 5, 6, 12.
Take a lcm of a, b, c = 60.
And divide by 5/60, 6/60, 12/60.

We get the answer of 12, 10,-5 because c can empty the tank it takes it as a negative term.
12 + 10 - 5 = 17.
Then divide by 60/17.
We get 3.58.

So, the answer is3(9/17).
(10)

Nisha said:   12 months ago
5'6'-12 LCM is 60.
So 12. 10. -5 then 12 + 10 - 5 = 17.
Then 60/17 = 3 (9/17) answer.
(7)


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