Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
1 13 hours
17
2 8 hours
11
3 9 hours
17
4 1 hours
2
Answer: Option
Explanation:

Net part filled in 1 hour 1 + 1 - 1 = 17 .
5 6 12 60

The tank will be full in 60 hours i.e., 3 9 hours.
17 17

Discussion:
57 comments Page 5 of 6.

Naushad said:   7 years ago
Dear Sir,

I think the pipes that filling the tank operates under constant pressure. So the flow rate is constant. But the pipe that is draining is operating under varying head, ie. Under varying pressure. So the draining of tank is not uniform, but proportional to the square root of the head. Hence the problem can't be solved using simple mathematics. For centuries we put it in wrong way.

Showkat bhat said:   7 years ago
(1/5 + 1/6 - 1/12) = (6+5/30 - 1/12).
= (11/30 -1/12),
= (132-30/360),
= (102/360)dividing numerator &denominator by 2,
= (51/180)dividing numerator &denominator by 3,
= (17/60).
(2)

Amudha said:   7 years ago
How it will come 17/60 to 60/17?

Kavi said:   7 years ago
@Neha how?
(51/180)dividing numerator &denominator by 2.
= (17/60).

Subiksha said:   7 years ago
I can't understand this. Anyone explain me clearly?
(1)

Shekhar said:   6 years ago
How 60/17 is converted into 3 (9/17)?

Please explain.

Ragavi said:   6 years ago
How to calculate it when the time is in minutes (intsead of hrs)? Please tell me.
(1)

Lavanya said:   6 years ago
Thanks all.

Rupa said:   6 years ago
@Sekhar.

17*3+9/60 = 60/17.

Sireeshadevi koppisetti said:   5 years ago
Thanks @Subrat Kumar Dhani.
(1)


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