Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 13)
13.
A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
3 hrs 15 min
3 hrs 45 min
4 hrs
4 hrs 15 min
Answer: Option
Explanation:

Time taken by one tap to fill half of the tank = 3 hrs.

Part filled by the four taps in 1 hour = 4 x 1 = 2 .
6 3

Remaining part = 1 - 1 = 1 .
2 2

2 : 1 :: 1 : x
3 2

x = 1 x 1 x 3 = 3 hours i.e., 45 mins.
2 2 4

So, total time taken = 3 hrs. 45 mins.

Discussion:
54 comments Page 6 of 6.

Tushar Pawar said:   3 years ago
They asked total time, so half tank is filled in 3 hour and later it takes 45 min as we calculated. Therefore 3 hour and 45 min.
(3)

Hemanth said:   2 years ago
We know Rate * Time = Capacity.

Rate = 1/6 ,
Capacity = 1/2.
1/6 * time =1/2
Here time = 3hrs for capacity half.
Next, more three pipes total of 4 pipes.
4 * 1/6 = 2/3.

Rate for 4 pipes is 2/3, Time=?, Capacity = another 1/2,
2/3 * time = 1/2.
Here time = 3/4 = 0.75hrs(0.75*60min).
Total time = 3hrs + 0.75hrs(45 min).
(9)

Sapna Singh Lodhi said:   9 months ago
The half tank filled in 3 hours since the full took 6 hours.
So, the rest half will be filled by 4 tap = 3 * 60/4 = 45.
Complete time to fill the tank = 3 hours 45 min.
(2)

Aditi chaudhary said:   2 weeks ago
Time taken by one tap to fill half of the tank = 3 hours.
Part filled by one tap in 1 hour = 1/6,
Part filled by 4 taps together in 1 hour = 4 × 1/6 = 2/3.

Total part filled by one tap + total part filled by 4 taps = 1.
(3)×(1/6) + (x)×(2/3) = 1.
[where x is the time taken by 4 taps to fill the tank].
Solving the equation we get, x = 3/4.
Now,
The Total time taken to fill the tank = 3 hours + 3/4 hours = 15/4 hours, which can also be written as 3(3/4) hours, which is 3 hours 45 minutes.
So, the correct option is (b) 3 hours 45 minutes.


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