Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 13)
13.
A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
Answer: Option
Explanation:
Time taken by one tap to fill half of the tank = 3 hrs.
| Part filled by the four taps in 1 hour = |  |
4 x | 1 |  |
= | 2 | . |
| 6 | 3 |
| Remaining part = | |
1 - | 1 | |
= | 1 | . |
| 2 | 2 |
 |
2 | : | 1 | :: 1 : x |
| 3 | 2 |
 x = |
|
1 | x 1 x | 3 | |
= | 3 | hours i.e., 45 mins. |
| 2 | 2 | 4 |
So, total time taken = 3 hrs. 45 mins.
Discussion:
53 comments Page 5 of 6.
Faysal said:
6 years ago
Quick one:
1 pipe fills half of the tank=6/=3 hrs.
Remaining half,
1 pipe takes 3 hr.
4 '' '' =3/4 hr= 45 mins.
Total = 3hrs+45mins(Answer)
1 pipe fills half of the tank=6/=3 hrs.
Remaining half,
1 pipe takes 3 hr.
4 '' '' =3/4 hr= 45 mins.
Total = 3hrs+45mins(Answer)
(2)
Gunjan said:
5 years ago
Thanks @Faysal.
(1)
Aadarsh kumar said:
5 years ago
As we know, rate * time =capacity.
So, after half filled.
A*3=4A *t
t=3/4 hour.
So total time taken is the time taken by A to fill half i.e 3 hr + 3/4 hr = 3 hr 45 minutes.
Thanks.
So, after half filled.
A*3=4A *t
t=3/4 hour.
So total time taken is the time taken by A to fill half i.e 3 hr + 3/4 hr = 3 hr 45 minutes.
Thanks.
(3)
Anomie said:
5 years ago
Tank filled in 1hr =6units.
For half an hour =3units.
Remaining 3units.
Now 3 more taps.....+previous 1 tap =4taps.
Efficiency =3/4.
Total =3*3/4(60)=3hr 45min.
For half an hour =3units.
Remaining 3units.
Now 3 more taps.....+previous 1 tap =4taps.
Efficiency =3/4.
Total =3*3/4(60)=3hr 45min.
M Ganesh said:
5 years ago
Here we are assuming rate =100
As per the statement,
A
R=100 h=? Capacity =300
=300/100=3.
A+B+C+D =300/400=0.75=45min
=> 3hr +45 min = 3hr 45.
As per the statement,
A
R=100 h=? Capacity =300
=300/100=3.
A+B+C+D =300/400=0.75=45min
=> 3hr +45 min = 3hr 45.
Sriramamurthi said:
5 years ago
Guys, it is very easy.
A tap can fill a tank by 6 hrs. Then one tap is closed after 6 hrs which means 6/2=3 hrs.
Then 3 more taps are opened so now totally there are 4 taps are opened.
We are having remaining time will be 6-3 =3 hrs.
So find 3/4 you get 0. 75 hrs which means 45 mins.
So the Answer will be 3hrs 45 mins.
Hope it will help you.
A tap can fill a tank by 6 hrs. Then one tap is closed after 6 hrs which means 6/2=3 hrs.
Then 3 more taps are opened so now totally there are 4 taps are opened.
We are having remaining time will be 6-3 =3 hrs.
So find 3/4 you get 0. 75 hrs which means 45 mins.
So the Answer will be 3hrs 45 mins.
Hope it will help you.
(12)
Gopi said:
5 years ago
@ Sravanthi :
only one tap fill the half tank. So, the remaining four should fill the remaining half tank.
Hence. 1 - 1/2 = 1/2.
It's should not be 1-2/3.
only one tap fill the half tank. So, the remaining four should fill the remaining half tank.
Hence. 1 - 1/2 = 1/2.
It's should not be 1-2/3.
GAGAn said:
5 years ago
It is assumed that all the taps are equally efficient, so we have divided 3 hrs, i.e 180 min into 4 equal part, that how 45 min came.
(10)
Teja said:
4 years ago
Time taken by 1tap to fill the tank is 6hrs, then half is 3hrs (work done by 1 tap).
So,
3 * (1/6) + x * (4/6) = 1,
x = 3/4.
So,
3 * (1/6) + x * (4/6) = 1,
x = 3/4.
(4)
Evans Twineamatsiko said:
3 years ago
Good explanation, Thanks. @Vicky!
(1)
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