Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 13)
13.
A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
Answer: Option
Explanation:
Time taken by one tap to fill half of the tank = 3 hrs.
Part filled by the four taps in 1 hour = | ![]() |
4 x | 1 | ![]() |
= | 2 | . |
6 | 3 |
Remaining part = | ![]() |
1 - | 1 | ![]() |
= | 1 | . |
2 | 2 |
![]() |
2 | : | 1 | :: 1 : x |
3 | 2 |
![]() |
![]() |
1 | x 1 x | 3 | ![]() |
= | 3 | hours i.e., 45 mins. |
2 | 2 | 4 |
So, total time taken = 3 hrs. 45 mins.
Discussion:
53 comments Page 4 of 6.
JISHNU said:
9 years ago
1 pipe takes 6 hrs to fill the tank.
So 1 pipe take 3 hrs to fill half the tank.
Other half is filled with 4 pipes,
The part of the tank filled with 4 pipes in 1 hr = 4 * 1/6 = 2/3.
So, the time taken to fill half the tank = (1/2) / (2/3)= (1/2) * (3/2) = 3/4 hrs= 45 minutes.
So the total time = 3hrs 45 minutes.
So 1 pipe take 3 hrs to fill half the tank.
Other half is filled with 4 pipes,
The part of the tank filled with 4 pipes in 1 hr = 4 * 1/6 = 2/3.
So, the time taken to fill half the tank = (1/2) / (2/3)= (1/2) * (3/2) = 3/4 hrs= 45 minutes.
So the total time = 3hrs 45 minutes.
Aditya said:
9 years ago
Thanks @Vicky.
Raja said:
9 years ago
Thanks @Vicky. That was clear and simple.
Vicky said:
9 years ago
Simple.
Tank takes to fill within 6 hours. So half of the tank we stop the waterfall. So half tank fills times 3 hours. So remaining half tank we use 4 pipes. Each pipes s similar so each pipe takes 3 hours to fill the tank. But here we open together all pipes.
The remaining 3 hours will be reduced by 4 pipes. 3 hours =180mins.
So we know 180/4 pipes = 45mins. So already half tank is filled.
Remaining the half tank has been filled withn 45 mins so, 3hours 45 mins is the answer.
Tank takes to fill within 6 hours. So half of the tank we stop the waterfall. So half tank fills times 3 hours. So remaining half tank we use 4 pipes. Each pipes s similar so each pipe takes 3 hours to fill the tank. But here we open together all pipes.
The remaining 3 hours will be reduced by 4 pipes. 3 hours =180mins.
So we know 180/4 pipes = 45mins. So already half tank is filled.
Remaining the half tank has been filled withn 45 mins so, 3hours 45 mins is the answer.
(1)
Amar said:
10 years ago
1. Time taken by a pipe to fill half the tank = 3 hrs.
2. So, time taken by 1st pipe along with 3 other similar pipes (i.e 4 pipes).
= 3 hrs/4.
= 180 min/4.
= 45 min.
Adding 1 and 2,
Total time taken = 3hr 45 min.
2. So, time taken by 1st pipe along with 3 other similar pipes (i.e 4 pipes).
= 3 hrs/4.
= 180 min/4.
= 45 min.
Adding 1 and 2,
Total time taken = 3hr 45 min.
Aparna said:
1 decade ago
2/3:1/2::1:x.
X = (1/2*1*3/2) = 3/4.
I did not got these two steps shall you explain me please in this step what is X why we should take the ratio.
X = (1/2*1*3/2) = 3/4.
I did not got these two steps shall you explain me please in this step what is X why we should take the ratio.
Kelvin said:
1 decade ago
One tap can fill tank completely in 6 hr.
Actually, tap's 1 hr work = 1/6.
--> Also, one tap can fill tank half in 3 hr.
--> When there are 3 more similar taps. Then total taps = 4.
4 tap's 1 hr work = 4/6.
Adding,
-->3/6 (since tap is filled half i.e. for 3 hrs by 1st tap) + x*4/6 = 1.
--> x because remaining x hr will be taken by 4 tap's to fill other half tank. Not necessarily 3 hr. That was taken by 1st tap alone.
On solving.
-->x = 3/4.
Getting total time = 3 hrs (tank filled half by 1st tap) + x.
--> 3+3/4.
-->15/4.
-->3:45 min.
Actually, tap's 1 hr work = 1/6.
--> Also, one tap can fill tank half in 3 hr.
--> When there are 3 more similar taps. Then total taps = 4.
4 tap's 1 hr work = 4/6.
Adding,
-->3/6 (since tap is filled half i.e. for 3 hrs by 1st tap) + x*4/6 = 1.
--> x because remaining x hr will be taken by 4 tap's to fill other half tank. Not necessarily 3 hr. That was taken by 1st tap alone.
On solving.
-->x = 3/4.
Getting total time = 3 hrs (tank filled half by 1st tap) + x.
--> 3+3/4.
-->15/4.
-->3:45 min.
Dee said:
1 decade ago
If 1 tap takes 6 hours --> 2 taps takes 6/2=3 (half time as fill faster).
If 2 taps takes 6/2=3 (half time)---4 taps takes 3/2=1.5 (i.e 1:30 min).
1:30 min= 60 min +30 min= 90 min.
90 min (time taken by 4 tapes to fill full tank).
But left is only half tank.
So 90/2 = 45 min.
Now total time = 3hour+45 min.
If 2 taps takes 6/2=3 (half time)---4 taps takes 3/2=1.5 (i.e 1:30 min).
1:30 min= 60 min +30 min= 90 min.
90 min (time taken by 4 tapes to fill full tank).
But left is only half tank.
So 90/2 = 45 min.
Now total time = 3hour+45 min.
Doctor said:
1 decade ago
1 tap takes 6 hours.
2 taps will take 3 hours.
Similarly 4 taps will take one and half hour i.e. 90 minutes to completely fill the tank.
Therefore, for half part it will take 45 minutes.
First tap will take 3 hours to half fill the tank.
Hence, we get 3 hours 45 minutes as answer.
2 taps will take 3 hours.
Similarly 4 taps will take one and half hour i.e. 90 minutes to completely fill the tank.
Therefore, for half part it will take 45 minutes.
First tap will take 3 hours to half fill the tank.
Hence, we get 3 hours 45 minutes as answer.
Shashank said:
1 decade ago
45 min are calculated as 3/4*60 = 3*15 = 45 min.
i:e 3/4 of 60 min(1 hr).
i:e 3/4 of 60 min(1 hr).
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