Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 13)
13.
A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
Answer: Option
Explanation:
Time taken by one tap to fill half of the tank = 3 hrs.
| Part filled by the four taps in 1 hour = |  |
4 x | 1 |  |
= | 2 | . |
| 6 | 3 |
| Remaining part = | |
1 - | 1 | |
= | 1 | . |
| 2 | 2 |
 |
2 | : | 1 | :: 1 : x |
| 3 | 2 |
 x = |
|
1 | x 1 x | 3 | |
= | 3 | hours i.e., 45 mins. |
| 2 | 2 | 4 |
So, total time taken = 3 hrs. 45 mins.
Discussion:
53 comments Page 6 of 6.
Lekha said:
1 decade ago
a,b,c,d=pipes 6 hrs time
a is taken=3 hrs time
a+a+b+c=3hrs each one taken 45 min
final 3hrs+45min
a is taken=3 hrs time
a+a+b+c=3hrs each one taken 45 min
final 3hrs+45min
Arun said:
1 decade ago
:: is the sign of proportionality
Sravanthi said:
2 decades ago
Time taken by 1 tap to fill half of the tank is =3hrs.
part filled by 4 taps in 1 hr=4*1/6=2/3.
then remaining part= 1-2/3=1/3 how is it 1/2 can anybody please tell
and what this ::symbol mean
part filled by 4 taps in 1 hr=4*1/6=2/3.
then remaining part= 1-2/3=1/3 how is it 1/2 can anybody please tell
and what this ::symbol mean
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