Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 13)
13.
A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
3 hrs 15 min
3 hrs 45 min
4 hrs
4 hrs 15 min
Answer: Option
Explanation:

Time taken by one tap to fill half of the tank = 3 hrs.

Part filled by the four taps in 1 hour = 4 x 1 = 2 .
6 3

Remaining part = 1 - 1 = 1 .
2 2

2 : 1 :: 1 : x
3 2

x = 1 x 1 x 3 = 3 hours i.e., 45 mins.
2 2 4

So, total time taken = 3 hrs. 45 mins.

Discussion:
53 comments Page 3 of 6.

Raja said:   9 years ago
Thanks @Vicky. That was clear and simple.

Aditya said:   9 years ago
Thanks @Vicky.

JISHNU said:   9 years ago
1 pipe takes 6 hrs to fill the tank.
So 1 pipe take 3 hrs to fill half the tank.
Other half is filled with 4 pipes,
The part of the tank filled with 4 pipes in 1 hr = 4 * 1/6 = 2/3.

So, the time taken to fill half the tank = (1/2) / (2/3)= (1/2) * (3/2) = 3/4 hrs= 45 minutes.
So the total time = 3hrs 45 minutes.

Nithin said:   9 years ago
Its pretty much a simple logic.

Tone tap 6 hrs to fill.

So 3 hrs to half fill.

A = 1/6.

4 taps 4a =4 * (1/6).

=> 2/3.

Now x be the tank capacity.

X/2 has filled already.

So remaining x/2 in 2/3.

X = 4/3 45 minutes.

So, totally 3 hrs 45 mts.

Kushagr said:   9 years ago
Considering the LCM of the all the four taps ie 6.

Now considering the capacity of tank be 6 units.

For the 1st half,

As only 1 tap is working so it fills 6/6 units/hr = 1 unit /hr (part filled by tap 1/total capacity of the tank).

As only 1 tap is working for the 1st half I.e. For 3 units of tank (total capacity of tank/2).

Calculations:

1 unit filled in 1 hr.

3 units filled in 3 hrs.

In second half 4 taps of same type are used, therefore it fills 4/6*6 = 4 units/hr (part filled by 4 taps/total capacity of the tank).

Now left out 3 units are filled by the combination of 4 taps.

Calculation:

4 units filled in 1 hr.

3 units filled in 3/4 hrs = 45 mins.

Therefore total time taken = time taken by 1st tap + time taken by combination of 4 similar taps.

= 3 hrs + 3/4 hrs = 3 hrs 45 mins.

Reshma rgukt basar said:   8 years ago
Here, given problem is that,

First half of the tank is filled in 3hrs by using only 1 tap.
After that 3 more pipes are opened so, now total working pipes 4(they are similar means takes the same time to fill the tank).

The remaining we have 6 - 3 = 3hrs.
3hrs means = 3 * 60 = 180min
So, equally this time shared by 4 pipes 180/4 = 45 min.
So total time is 3hrs 45 min.

Sajan said:   8 years ago
I think logic behind 2/3 :3::1:x is;

X is the time taken by 4 tap to fill remaining 1/2 in hours.
AND, 2/3 part of tank is filled in 1 hour.
So, (2/3)/(1/2) = 1hr/xhr
Which can b also written as
2/3 : 3 :: 1.

To verify put 45 in place of X and check if the ratio r equal or not(deal in minutes what I mean is that conversation 1hr into 60 minute.

So, 1/x becomes 60/45 that is 4/3. And also, 2/3 : 1/2 is 4/3.

Suvit said:   8 years ago
The first tank will take 3hrs to fill in half of the tank.

4 tanks will take 6/4=1.5hrs to fill the full tank.
but as half of the tank is already filled, it will take 0.75hr=45mins for the rest half tank.

Sandy said:   8 years ago
It will take less than 24 hours. How?

Jay said:   8 years ago
It should be:

2/3 : 1 :: 1/2 : x.


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