Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 8)
8.
In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
Answer: Option
Explanation:
| Required number of ways | = (8C5 x 10C6) | |||||||
| = (8C3 x 10C4) | ||||||||
|
||||||||
| = 11760. |
Discussion:
61 comments Page 5 of 7.
Priya said:
10 years ago
When I'm solving it directly like 8C5 and 10C6 means I'm getting wrong answer.
Tejal said:
8 years ago
Don't we have to divide (8C5*10C6) by total no of selection that is 18C11?
Nancy said:
8 years ago
Please help me to understand why the deduction (the second step) is done?
Prakash said:
6 years ago
Kindly anyone tells the difference between permutations and combinations.
(1)
Pankaj kumar said:
7 years ago
The second step involves the formula of nCr,
which is;
nCr = n!/(n-r)!r!.
which is;
nCr = n!/(n-r)!r!.
Sundar said:
1 decade ago
Hi Farjana,
Thanks for your valuable information. Have a nice day!
Thanks for your valuable information. Have a nice day!
Rahul said:
7 years ago
I am not getting this answer. Please, anyone, help me to get this.
Deepu2543651 said:
1 decade ago
Why we getting wrong answer while we directly apply nCr formula?
Musa said:
1 decade ago
I don't understand the formula used. Can somebody explain it?
Charan said:
8 years ago
6men and 5 women can also be changed so it can be 11!*11760.
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