Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 8)
8.
In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
Answer: Option
Explanation:
| Required number of ways | = (8C5 x 10C6) | |||||||
| = (8C3 x 10C4) | ||||||||
|
||||||||
| = 11760. |
Discussion:
61 comments Page 3 of 7.
Younisali.syed said:
1 decade ago
I agree with this answer but when you see question no: 4 in that he selected and then arranged in this problem he only selected.
Any one tell me why so?
Any one tell me why so?
Flair said:
1 decade ago
In this question don't give importance to arrangements. Like ABC=ACB=BAC they are same. Take this example with person.
Siva said:
1 decade ago
Different arrangement of digits in a number gives different numbers, but arrangement doesn't alter the composition of a committee. So no need to calculate no.of arrangements. All arrangements give the same committee.
Nishat Parwez said:
1 decade ago
The correct formula for the mentioned question is n!/r!( n-r)!..
This makes the concept clear. Totally agree with @Diwakar.
This makes the concept clear. Totally agree with @Diwakar.
Vishesh bakshi said:
1 decade ago
Am always confused whether to multiply or add in between this two cases. How to determine it correctly can any one help me out on this?
Poonam said:
1 decade ago
Do not use the formula which does not exist for actual solution. That formula is for permutation which you given. Please explain in another way.
Bala said:
1 decade ago
Ya its confusing please tell in simple way.
Priya said:
10 years ago
When I'm solving it directly like 8C5 and 10C6 means I'm getting wrong answer.
Karthika said:
10 years ago
Why we are applying the ncr=n-r formula in the second step?
What is the purpose of using where we should we use this?
What is the purpose of using where we should we use this?
Webuzzi said:
10 years ago
Why all should try this formula you will still get the right answer n!/(n!-r!)r!.
8!/(8!-5!)5! which will yield 56 then use same formula and solve for 10 combination 6 it will yield 210. Then multiply the former result by the later result. That is 56 multiplied by 210 will yield 11760.
8!/(8!-5!)5! which will yield 56 then use same formula and solve for 10 combination 6 it will yield 210. Then multiply the former result by the later result. That is 56 multiplied by 210 will yield 11760.
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