Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 8)
8.
In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
Answer: Option
Explanation:
| Required number of ways | = (8C5 x 10C6) | |||||||
| = (8C3 x 10C4) | ||||||||
|
||||||||
| = 11760. |
Discussion:
61 comments Page 2 of 7.
Sayali said:
6 years ago
nCr=n!/r! (n-r)! =8C5=8! /5!* 3! = 56.
&
10C6=10! /6! *4! =210.
Therefore, 56*210 = 11760.
&
10C6=10! /6! *4! =210.
Therefore, 56*210 = 11760.
(4)
Mohan said:
6 years ago
8C5 = (8*7*6*5*4)/(5*4*3*2*1).
= (8*7*6)/(3*2*1).
= 8C3.
10C6 = (10*9*8*7*6*5)/(6*5*4*3*2*1).
= (10*9*8*7)/(4*3*2*1),
= 10C4.
= (8*7*6)/(3*2*1).
= 8C3.
10C6 = (10*9*8*7*6*5)/(6*5*4*3*2*1).
= (10*9*8*7)/(4*3*2*1),
= 10C4.
(5)
Rahul said:
7 years ago
I am not getting this answer. Please, anyone, help me to get this.
Shivani Bairagi said:
7 years ago
Why we take 8C3 * 10C4?
I am not understanding. So please explain me in detail.
I am not understanding. So please explain me in detail.
B S said:
7 years ago
The Answer should be 266.
Pankaj kumar said:
7 years ago
The second step involves the formula of nCr,
which is;
nCr = n!/(n-r)!r!.
which is;
nCr = n!/(n-r)!r!.
Nancy said:
8 years ago
Please help me to understand why the deduction (the second step) is done?
Tejal said:
8 years ago
Don't we have to divide (8C5*10C6) by total no of selection that is 18C11?
Gayudhaya said:
8 years ago
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
By using above formula just explain it.
By using above formula just explain it.
Charan said:
8 years ago
6men and 5 women can also be changed so it can be 11!*11760.
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