Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 8 of 18.
Prakhar Maheshwari said:
7 years ago
Answer is C.
I have directly used option to get the answer.
So, 42/75*100 =56%; (42+33 =75).
I have directly used option to get the answer.
So, 42/75*100 =56%; (42+33 =75).
Sai said:
7 years ago
We can easily say by seeing option also for time-saving.
Take total Mark's =100
One's mark is 56 % of sum
So here the sum is 100
56% of 100 is 56
And remaking Mark's is 44
So its in the ratio of 44:56
We can take 11*4:14*4
11x:14x
So the Marks are multiple of 11 and 14.
Thank you.
Take total Mark's =100
One's mark is 56 % of sum
So here the sum is 100
56% of 100 is 56
And remaking Mark's is 44
So its in the ratio of 44:56
We can take 11*4:14*4
11x:14x
So the Marks are multiple of 11 and 14.
Thank you.
Vel7 said:
7 years ago
Take option c. 42, 33.
Then 42+33=75 so, 75= 100%.
7.5=10%.
0.75=1%.
We calulate 56% 1%= 0.75.
56%=0.75*56= 42
Difference 9. So 42-9=33.
Then 42+33=75 so, 75= 100%.
7.5=10%.
0.75=1%.
We calulate 56% 1%= 0.75.
56%=0.75*56= 42
Difference 9. So 42-9=33.
Kalyan said:
8 years ago
Let both of them be A and B.
Given A= 9+X and B = x.
Also A = 56% of their total marks;
So, A = 56/100 * (9+x+x).
Where A= 9+x.
By equating we can get x value 33.
A = 33+9 = 42.
Given A= 9+X and B = x.
Also A = 56% of their total marks;
So, A = 56/100 * (9+x+x).
Where A= 9+x.
By equating we can get x value 33.
A = 33+9 = 42.
(1)
Sushmitha said:
8 years ago
25(x+9) = 14(2x+9) how its came?
Please explain this step.
Please explain this step.
Nishant said:
8 years ago
It's actually very simple!! If 1 student got 56%, then other student % must be 100-56%=44%.
Now 56%- 44%=12%.
12%=9(the difference between the marks of both the students).
You can solve it now!
Now 56%- 44%=12%.
12%=9(the difference between the marks of both the students).
You can solve it now!
Waqar said:
8 years ago
Thanks @Ashok.
Jajjo said:
8 years ago
How you can take 25 at lhs and 14 rhs?
Vinaya said:
8 years ago
Thanks @Tukuna.
Lingeswaran said:
8 years ago
Thanks @Aman Tomar.
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