Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 7 of 17.
Roja said:
9 years ago
Thank you @Ganesh.
Piyush Pankaj said:
9 years ago
Thanks @Neelu.
Karthikeyan said:
9 years ago
Can you please explain why we keep in x + 9 on the left side?
DURGAO said:
9 years ago
Thank you @ Radhika.
Santanu said:
9 years ago
56% - 44% = 9.
100% = 75.
Which total makes 75. That's it.
100% = 75.
Which total makes 75. That's it.
Satheeshkumar said:
9 years ago
How 25 came? Please explain that.
Archana Gaikwad said:
9 years ago
56% - 44 = 9.
But please explain 100% = 75.
& How 25 come?
But please explain 100% = 75.
& How 25 come?
Mohan said:
9 years ago
To my understanding.
Student 2 score = x.
Student 1 score 9 marks more than student 2 = x + 9 which is 56 percent of the total marks(x + x + 9) right.
x + 9 = 56%(x + x + 9).
Solving the above equation we will get x = 33 which is student 2 mark.
Student 1 has scored 9 marks more than student 2 so 33 + 9 = 42.
Student 2 score = x.
Student 1 score 9 marks more than student 2 = x + 9 which is 56 percent of the total marks(x + x + 9) right.
x + 9 = 56%(x + x + 9).
Solving the above equation we will get x = 33 which is student 2 mark.
Student 1 has scored 9 marks more than student 2 so 33 + 9 = 42.
ISHITA said:
9 years ago
I can not understand the question. Please someone explain me.
Sujay said:
9 years ago
Let their marks be(x + 9)and x.
Then, x+9 =56/100(x + 9 + x),
= 25(x + 9)= 14(2x + 9),
= 3x = 99,
x = 33.
So,there marks are 42 and 33.
Then, x+9 =56/100(x + 9 + x),
= 25(x + 9)= 14(2x + 9),
= 3x = 99,
x = 33.
So,there marks are 42 and 33.
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