Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 15 of 17.
Vel7 said:
7 years ago
Take option c. 42, 33.
Then 42+33=75 so, 75= 100%.
7.5=10%.
0.75=1%.
We calulate 56% 1%= 0.75.
56%=0.75*56= 42
Difference 9. So 42-9=33.
Then 42+33=75 so, 75= 100%.
7.5=10%.
0.75=1%.
We calulate 56% 1%= 0.75.
56%=0.75*56= 42
Difference 9. So 42-9=33.
Sai said:
7 years ago
We can easily say by seeing option also for time-saving.
Take total Mark's =100
One's mark is 56 % of sum
So here the sum is 100
56% of 100 is 56
And remaking Mark's is 44
So its in the ratio of 44:56
We can take 11*4:14*4
11x:14x
So the Marks are multiple of 11 and 14.
Thank you.
Take total Mark's =100
One's mark is 56 % of sum
So here the sum is 100
56% of 100 is 56
And remaking Mark's is 44
So its in the ratio of 44:56
We can take 11*4:14*4
11x:14x
So the Marks are multiple of 11 and 14.
Thank you.
Prakhar Maheshwari said:
7 years ago
Answer is C.
I have directly used option to get the answer.
So, 42/75*100 =56%; (42+33 =75).
I have directly used option to get the answer.
So, 42/75*100 =56%; (42+33 =75).
Vasu said:
7 years ago
How it is 56-44/100=12?
Girish P said:
7 years ago
Easiest way to solve this is as follows:
The total percentage of marks is 56%,
so divide 56 by 2,
You get 33, 1%=6 marks, the student has scored 9 marks more so,
33+9=42, the other student marks will be 9 marks less so simple,
42-9=33.
ANSWER=42 & 33.
The total percentage of marks is 56%,
so divide 56 by 2,
You get 33, 1%=6 marks, the student has scored 9 marks more so,
33+9=42, the other student marks will be 9 marks less so simple,
42-9=33.
ANSWER=42 & 33.
Rohan said:
7 years ago
@Hiren Savalia.
Can you elaborate your method?
Can you elaborate your method?
MUKUL said:
7 years ago
Let's take x, x+9; of their marks.
x=44/100*(x+x+9) or -+9=56/100*(x+x+9).
Solve; eq x =33. And another x+9.
33+9=42.
x=44/100*(x+x+9) or -+9=56/100*(x+x+9).
Solve; eq x =33. And another x+9.
33+9=42.
Roopsingh said:
7 years ago
How come 56/100? Please explain in detail.
Dsr said:
7 years ago
Good explanation, Thanks all.
Nagesh v said:
7 years ago
Thank you @Shrikant.
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