Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
174 comments Page 13 of 18.
Umang gandhi said:
10 years ago
Let two student a&b.
a scores 9 marks more than b and have 56%.
a = 56%.
b = 100-56 = 44%,
56% = 9 + 44%,
12% = 9.
Let total marks be x.
12%X = 9,
(12/100) * x = 9,
x = 75.
Sum of both a and b = 75.
We check option which satisfies above condition = 42, 33.
a scores 9 marks more than b and have 56%.
a = 56%.
b = 100-56 = 44%,
56% = 9 + 44%,
12% = 9.
Let total marks be x.
12%X = 9,
(12/100) * x = 9,
x = 75.
Sum of both a and b = 75.
We check option which satisfies above condition = 42, 33.
Borra vamsi krishna said:
10 years ago
Please explain in simple way.
Megha said:
10 years ago
In an exam, 5%of the application were found ineligible &85% of the eligible candidates belongs to general category. If 4275 eligible candidates belonged to other categories, then how much candidates applied for the exam?
Please answer this question.
Please answer this question.
Dinesh D said:
10 years ago
@Aniket.
Let the total number of candidates who applied be x.
Ineligible candidates = 0.05x.
Eligible candidates = x-0.05x = 0.95x.
General category candidates who are eligible = (0.95x)*0.85 = 0.8075x.
Other category candidates who are eligible = 4275.
Then x = 0.05x + 4275+0.8075x.
= 0.8575x + 4275.
0.1425x = 4275.
x = 30000.
Let the total number of candidates who applied be x.
Ineligible candidates = 0.05x.
Eligible candidates = x-0.05x = 0.95x.
General category candidates who are eligible = (0.95x)*0.85 = 0.8075x.
Other category candidates who are eligible = 4275.
Then x = 0.05x + 4275+0.8075x.
= 0.8575x + 4275.
0.1425x = 4275.
x = 30000.
Purwa said:
9 years ago
Great explanation, thanks @Neelu.
Bhusan said:
9 years ago
Hi, can you please explain it came?
Then, x + 9 = 56 (x + 9 + x)
100
25(x + 9) = 14(2x + 9).
If we divide with 4 by 56/100 then the answer is 25 and 14. My question is how 4 came into picture?
Then, x + 9 = 56 (x + 9 + x)
100
25(x + 9) = 14(2x + 9).
If we divide with 4 by 56/100 then the answer is 25 and 14. My question is how 4 came into picture?
Albert Einstein said:
9 years ago
Let their marks be (x + 9) and x.
Then, x + 9 = 56/100(x + 9 + x).
25(x + 9) = 14(2x + 9),
3x = 99,
x = 33.
So, their marks are 42 and 33.
Then, x + 9 = 56/100(x + 9 + x).
25(x + 9) = 14(2x + 9),
3x = 99,
x = 33.
So, their marks are 42 and 33.
Hari said:
9 years ago
25(x+9) = 14(2x+9).
Why 25 came here? Explain briefly.
Why 25 came here? Explain briefly.
Raja said:
9 years ago
Explain it.
In an exam, 5%of the application were found ineligible &85% of the eligible candidates belongs to general category. If 4275 eligible candidates belonged to other categories, then how much candidates applied for the exam?
90% application is a general category and ineligible. So balance 10%are other categories and it's 4275 application. So 10%is equal to 4275 then 100% is equal to 42750 application.
In an exam, 5%of the application were found ineligible &85% of the eligible candidates belongs to general category. If 4275 eligible candidates belonged to other categories, then how much candidates applied for the exam?
90% application is a general category and ineligible. So balance 10%are other categories and it's 4275 application. So 10%is equal to 4275 then 100% is equal to 42750 application.
Nikhila said:
9 years ago
Where you get 25 and 14? Please tell me.
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