Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 7)
7.
In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 
of the number of students of 8 years of age which is 48. What is the total number of students in the school?
Answer: Option
Explanation:
Let the number of students be x. Then,
Number of students above 8 years of age = (100 - 20)% of x = 80% of x.
 80% of x = 48 + |
2 | of 48 |
| 3 |
 |
80 | x = 80 |
| 100 |
x = 100.
Video Explanation: https://youtu.be/yPfocU6DA2M
Discussion:
135 comments Page 7 of 14.
Johnson said:
1 decade ago
It is the language of the question that creates confusion. It is not clear whether no. of students ab0ve 8 is 48 0r students of 8 years age is 48.
RAJIB KUMAR KOHAR said:
9 years ago
Students at the age of 8 = 48,
Students above age of 8 = 2/3 of 48 = 32,
Students at the age of 8 = 20,
Total students = (48 + 32 + 20) = 100.
Students above age of 8 = 2/3 of 48 = 32,
Students at the age of 8 = 20,
Total students = (48 + 32 + 20) = 100.
Puja said:
7 years ago
Let total student =100.
8year below=20,
Now 100-20=80,
8 year= 48,
80-48=32,
Which is equal to 8year above..
Total student= 20 +32+48=100.
8year below=20,
Now 100-20=80,
8 year= 48,
80-48=32,
Which is equal to 8year above..
Total student= 20 +32+48=100.
Aruna B said:
2 years ago
Below 8y= 20%,
8 y= 48.
Above 8 y=2/3 of48 = 32.
Let no.of students be x.
20% x = x - 80,
20/100x = x - 80,
80 = x - 20/100x.
x = 100.
8 y= 48.
Above 8 y=2/3 of48 = 32.
Let no.of students be x.
20% x = x - 80,
20/100x = x - 80,
80 = x - 20/100x.
x = 100.
(23)
Deepan said:
8 years ago
Hi, According to me,
We are calculating upto 80% and what about remaining 20%?
So, [80%+20%]=[100+25],
No.of students = 125.
We are calculating upto 80% and what about remaining 20%?
So, [80%+20%]=[100+25],
No.of students = 125.
Saket said:
4 years ago
Let total student be x.
Then
20% of x +48+2/3 of 48=x.
Implies, x/5-x+80=0.
or, x=80*5/4=100.
Total no of students =100.
Then
20% of x +48+2/3 of 48=x.
Implies, x/5-x+80=0.
or, x=80*5/4=100.
Total no of students =100.
Kiran BS said:
6 years ago
Let total no of students be X.
Now according to question 20%X + 2/3 of 48 + 48 =X.
On solving the above equation you get X.
Now according to question 20%X + 2/3 of 48 + 48 =X.
On solving the above equation you get X.
Pradeep said:
7 years ago
x students in total,
(100 - 20)% * x = 80% * x.
80/100 * x = 48+(2/3)48,
(80/100)*x=48+32=80,
80% is 80, then 100% of 100.
(100 - 20)% * x = 80% * x.
80/100 * x = 48+(2/3)48,
(80/100)*x=48+32=80,
80% is 80, then 100% of 100.
Naresh said:
1 decade ago
Can you explain me when should we take 100-20 in the above given problem and then whats the need to consider it for 100%?
Prawin said:
2 decades ago
80% of x (means no of student havin age, 8 and above ) = 48(no of student of age =8)+2/3 of 48(studens abov age 8)
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