Aptitude - Percentage - Discussion

No.of students of 8 yrs - 48.
No.of students of above 8 yrs - 2/3 of 8 yrs old stud.
So, 2/3*48 = 32.
Total students of 8 yrs and above 8 yrs = 48 + 32 = 80 students.

Now, out of the total students, only 20% of them are below 8 years old. We don't know how many are total students yet. So let's assume the total students as X.
Students below 8 years old -X*20/100(20% is written as 20/100).
= 20x/100.

Total students in school,
80(8yr & above 8 yr total) + 20x/100(below 8yrs total) = x(total students in school that we assumed as x).
80 + 20x/100 = x.
//Take LCM for 80+20x/100.
(8000+20x)/100 = x.
//Bring the denominator 100 to the right side to multiply with x.
8000 + 20x = 100x.
8000 = 80x.
x = 100.

Let a total number of the student be 100% out of which 20% of students are below 8years of age so remaining 80% of students are either 8years of age or above 8years of age.

No of students of 8years age=48(given)


No of students above 8years age=2/3* no of students of 8years age
= 2/3*48,
= 32.

80% of students= no of students of 8years age + no of student above 8years age.
80% of students=48+32,
=80.
(We have to find total students in the school so)

100% of students=80/80*100.
=100.

Total number of students in the school are 100.

FOR You @ANKIT.

LET total no.of students = x.
According to question below 8 years = 20% of x, i.e = 20x/100.

Again acc. to question no.of exact years = 48 and no.of above 8 years = two third of number. exact 8 year i.e = 2/3 of 48 = 32.

Now no.of exact 8 years = 48, above 8 years = 32 and below 8 years = 20x/100.

So total no.of students = 48+32+20x/100 = x(that we have taken at beginning),

So now 80+20x/100 = x,
20x/100 = x-80,
20x = 100x-8000,
100x-20x = 8000,
80x = 8000,
x = 8000/80 = 100(i.e total no.of students) ANS.

I THINK YOU UNDERSTAND..THANK YOU.

Don't use XYZ, it's easier to buy one method i.e.

Below 8 year students = 20%.
And above 8 year students = 48,
And 8 year students = 2/3 of 8 year students,
=> (2/3)*48 => 32.

Simply things if 20% of students below 8 then same and above year students % will be = 100%-20% = 80%,
Then,
80% = 8yr students+8yr above students.
=>80% =48+32.
=>80%=80.
if 80 % students = 80.
Then 1% students =80/80 =1.
Then 100% students =100*1=100.
The total students are 100.

Let students <8 = 20%.
Let students >8 = 2/3(48).
Let students who are 8 = 48.

Now let's calculate students >8,
which is 2/3(48)=96/3=32

Now combine students who are >8 and students who are 8.
which is 32 + 48 = 80.

Now we have to find student <8 which is 20% of the whole class
We got the remaining 80% which is 80. so what percent should be added with 80% to make it 100%?
It is 20%.

So if 80% is 80 then 20% is 20.
which is total students 80 + 20 = 100.

@All.
Here is my solution.

Total Number of Students = X.
Less than 8 Years age Students = 20 % of X = (20/100) * X.
8 Years Age Students = 48,
c = (2/3) * 48 = 32.

Total Number of Students = X = Less than 8 Years age Students + 8 Years Age Students + 8 Years Age Students
X = (20/100) * X + 48+32.
X = (20/100) * X + 80.
X = (20X+8000)/100.
100X = 20X+8000.
80X = 8000.
X = 8000/80.
Total Number of Students = X= 100.

Let the total students be x.

20%of x = No of students below age 8.

48 = No of students of age exact 8. Given.

No of students above age 8 is 2/3 of no of students of age exact 8.

That is 2/3 of 48 = 32.

So above 8 is 32.

Exact 8 is 48x. Total of above is 80.

Now students below age 8 is 20% of total.

Therefore 20/100 of x = (x-80).

20x = 100x-8000.
8000 = 80x.
x = 100.

Therefore answer is 100.

Under these question, three categories have come i.e,

1. Less than 8 years aged students(A)
2. exact 8 years aged students(C)
3. Greater than 8 years students.(B)

Total no. of students (x) = A+B+C.

We know C=48 no,
From question A= 20%x,
and Remaining B&C=100-20,
=80%.

Then (80/100)x= C+(2/3)C (Where B=(2/3) of C),
(80/100)X= 48+(2/3)48.

By Resolving this X=100 is the answer.

Hi answer is 100.

Here they mentioned above 8 year old students are 2/3 of 48 of age 8.

So 2/3 of 48 = 32.

So 32+48 = 80.

Now we left with 20% of students which are below 8.

There will be maximum 100% so they asking 20%.

We already found 80% of the students strength i.e. 80.

So 20% of 100 is 20. So 80(8 year+above 8 year) + 20(less than 8) = 100.

Hope you guys got it.

Let The Total No.of Students are = 100.
So 20% Students are 8 year below = 100X20% /100 = 20.

Than The No.of Students of 8 year below = 20.
And No.of Students 8 year are = 48.

Now No.of Students are above 8 Year = 2/3 X 48.
= 32.

So The Total No. of Students are = 20+48+32.
= 100 , Option (E).