Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 7)
7.
In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is of the number of students of 8 years of age which is 48. What is the total number of students in the school?
Answer: Option
Explanation:
Let the number of students be x. Then,
Number of students above 8 years of age = (100 - 20)% of x = 80% of x.
![]() |
2 | of 48 |
3 |
![]() |
80 | x = 80 |
100 |
x = 100.
Video Explanation: https://youtu.be/yPfocU6DA2M
Discussion:
135 comments Page 1 of 14.
Suruthikaa G said:
2 years ago
Simply;
Students below age of 8= 20%
Students above age of 8= 2/3,
Students in age of 8= 48.
48*2/3= 32.
32+48= 80%.
80%+20%=100%.
So, 100 students.
Students below age of 8= 20%
Students above age of 8= 2/3,
Students in age of 8= 48.
48*2/3= 32.
32+48= 80%.
80%+20%=100%.
So, 100 students.
(89)
Lily said:
1 year ago
Let,
The no of students = 100
Now, 20% of 100 =20
Above 8 years old are = 48
And 8 years old are :
2/3 of 48
= 32.
Now, the total no of students are: 48 + 32 + 20 = 100.
The no of students = 100
Now, 20% of 100 =20
Above 8 years old are = 48
And 8 years old are :
2/3 of 48
= 32.
Now, the total no of students are: 48 + 32 + 20 = 100.
(62)
Khirod said:
2 years ago
8 years below = 20%.
8 years above= ⅔ x 48 is 32.
8 years = 48.
Total students = 100%.
Then, 8 years above + 8 years below + 8 years = 100%.
20%. Below the rest 80%,
80% = 32+ 48,
80% = 80.
Then 100 % = 80/80 = 1.
20%= 20.
Total students 20 + 32 + 48 = 100.
8 years above= ⅔ x 48 is 32.
8 years = 48.
Total students = 100%.
Then, 8 years above + 8 years below + 8 years = 100%.
20%. Below the rest 80%,
80% = 32+ 48,
80% = 80.
Then 100 % = 80/80 = 1.
20%= 20.
Total students 20 + 32 + 48 = 100.
(61)
Bimal said:
11 months ago
Let students <8 = 20%.
Let students >8 = 2/3(48).
Let students who are 8 = 48.
Now let's calculate students >8,
which is 2/3(48)=96/3=32
Now combine students who are >8 and students who are 8.
which is 32 + 48 = 80.
Now we have to find student <8 which is 20% of the whole class
We got the remaining 80% which is 80. so what percent should be added with 80% to make it 100%?
It is 20%.
So if 80% is 80 then 20% is 20.
which is total students 80 + 20 = 100.
Let students >8 = 2/3(48).
Let students who are 8 = 48.
Now let's calculate students >8,
which is 2/3(48)=96/3=32
Now combine students who are >8 and students who are 8.
which is 32 + 48 = 80.
Now we have to find student <8 which is 20% of the whole class
We got the remaining 80% which is 80. so what percent should be added with 80% to make it 100%?
It is 20%.
So if 80% is 80 then 20% is 20.
which is total students 80 + 20 = 100.
(33)
JAYASURYA P said:
9 months ago
8 years below student = 20%
assume total percentage = 100%
8 years student(given) = 48.
8 years above = remaining of below 8 years student.
so 100%-20%= 80%.
then, 80(above 8 years).
student=(above + below + same level).
So, 80-48(same 8 years) = 32(above 8 years).
Total = 20 + 32 + 48 = 100.
assume total percentage = 100%
8 years student(given) = 48.
8 years above = remaining of below 8 years student.
so 100%-20%= 80%.
then, 80(above 8 years).
student=(above + below + same level).
So, 80-48(same 8 years) = 32(above 8 years).
Total = 20 + 32 + 48 = 100.
(29)
Pappa said:
9 months ago
20% + 48 = 68.
100 - 68 = 32.
20 + 32 + 48 = 100.
100 - 68 = 32.
20 + 32 + 48 = 100.
(26)
Aruna B said:
2 years ago
Below 8y= 20%,
8 y= 48.
Above 8 y=2/3 of48 = 32.
Let no.of students be x.
20% x = x - 80,
20/100x = x - 80,
80 = x - 20/100x.
x = 100.
8 y= 48.
Above 8 y=2/3 of48 = 32.
Let no.of students be x.
20% x = x - 80,
20/100x = x - 80,
80 = x - 20/100x.
x = 100.
(23)
Krushna said:
3 years ago
Given;
20% below 8 year of age. (100%- 20% ) = 80%.
80 % = age of students equal to 8 yr + age of students above 8 yr.
80 % of Total students = 48 + 2/3 * 48.
80% of Total students = 48+32 = 80
(80/100)* Total students = 80
Total Students = 80 *(100/80) = 100.
20% below 8 year of age. (100%- 20% ) = 80%.
80 % = age of students equal to 8 yr + age of students above 8 yr.
80 % of Total students = 48 + 2/3 * 48.
80% of Total students = 48+32 = 80
(80/100)* Total students = 80
Total Students = 80 *(100/80) = 100.
(20)
PADMAVATHI said:
5 months ago
GIVEN:-
20% of students [below 8yrs],
2/3 of no of students of 8yrs i.e 48 [above 8yrs]
Total no of "students" (x)= 100.
SOLUTION:
1) 20% of students (x).
=20/100 * 100 = 20 students.
2) 2/3 of students of 8yrs (48),
= 2/3 * 48 = 32 students.
3) = 20 + 32 + 48(already given) = 100 students[ANSWER].
20% of students [below 8yrs],
2/3 of no of students of 8yrs i.e 48 [above 8yrs]
Total no of "students" (x)= 100.
SOLUTION:
1) 20% of students (x).
=20/100 * 100 = 20 students.
2) 2/3 of students of 8yrs (48),
= 2/3 * 48 = 32 students.
3) = 20 + 32 + 48(already given) = 100 students[ANSWER].
(17)
Hemant Asthana said:
3 years ago
x is a total number of students. Then According to the question,
x = 48 + 2/3*48 + 20% of x,
x = 48 + 32 + x/5,
4x/5 = 80,
x = 100 (total number of students).
x = 48 + 2/3*48 + 20% of x,
x = 48 + 32 + x/5,
4x/5 = 80,
x = 100 (total number of students).
(16)
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