Aptitude - Percentage - Discussion

@Moorthy.

100% - 20% whose age are below 8 = 80%.

Now remaining part is given in that sub part is 48 people are equal to 8 years of age.

And tge people who are in between 8 years I. E in between of equal to 8 and below 8 is 2/3 of 48.

Total = below 8 years + equal to 8 years + more than 8 years = 100.

Let the no.of students = x.

Total students = below 8 + exact 8 + above 8.
X = (20/100) + 48 + 2/3(48),
X = 20x/100 + 48 + 32,
X - 20x/100 = 80,
80x/100 = 80,
X = 100.

Don't use XYZ, it's easier to buy one method i.e.

Below 8 year students = 20%.
And above 8 year students = 48,
And 8 year students = 2/3 of 8 year students,
=> (2/3)*48 => 32.

Simply things if 20% of students below 8 then same and above year students % will be = 100%-20% = 80%,
Then,
80% = 8yr students+8yr above students.
=>80% =48+32.
=>80%=80.
if 80 % students = 80.
Then 1% students =80/80 =1.
Then 100% students =100*1=100.
The total students are 100.

Let,

Total number of student = x.
Given as,
8 years age = 48
8 years above age = 48 *(2/3)
= 32.

Below 8 years age = x * 20%.

By condition,

X*20%+32+48 = x,
Or, x*(20÷100) +80 = x,
Or, x - x/5 =80,
Or, (5x-x)/5 = 80,
Or,4x/5 = 80,
Or, x = (80*5)/4,
Or, x = 100.
So, a total number of students = 100.

Ans: 100.

Let total student be x.

Then
20% of x +48+2/3 of 48=x.
Implies, x/5-x+80=0.
or, x=80*5/4=100.
Total no of students =100.