Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 7)
7.
In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 
of the number of students of 8 years of age which is 48. What is the total number of students in the school?
Answer: Option
Explanation:
Let the number of students be x. Then,
Number of students above 8 years of age = (100 - 20)% of x = 80% of x.
 80% of x = 48 + |
2 | of 48 |
| 3 |
 |
80 | x = 80 |
| 100 |
x = 100.
Video Explanation: https://youtu.be/yPfocU6DA2M
Discussion:
135 comments Page 6 of 14.
Abhijit mane said:
1 decade ago
Total = x.
Below 8 years = 20/100 * x .
= 2/10x.
Above 8 years = 2/3 * 48.
= 32.
Total = 2/10x + 32 + 48 = x.
x = 100.
Below 8 years = 20/100 * x .
= 2/10x.
Above 8 years = 2/3 * 48.
= 32.
Total = 2/10x + 32 + 48 = x.
x = 100.
Vinod Anand said:
1 decade ago
Let The Total No.of Students are = 100.
So 20% Students are 8 year below = 100X20% /100 = 20.
Than The No.of Students of 8 year below = 20.
And No.of Students 8 year are = 48.
Now No.of Students are above 8 Year = 2/3 X 48.
= 32.
So The Total No. of Students are = 20+48+32.
= 100 , Option (E).
So 20% Students are 8 year below = 100X20% /100 = 20.
Than The No.of Students of 8 year below = 20.
And No.of Students 8 year are = 48.
Now No.of Students are above 8 Year = 2/3 X 48.
= 32.
So The Total No. of Students are = 20+48+32.
= 100 , Option (E).
Karthik swathi said:
1 decade ago
Here asking the total no.of students, then why u equal to the 80% (which is above 8 year).
DURAI said:
1 decade ago
Total no of students = no.of students below 8 yrs + no.of students exact 8 yrs + no.of students above 8 yrs.
Given data:
no.of students 8 yrs exact = 48.
no.of students above 8 yrs = 2/3 of 48 = 32.
no.of students below 8 yrs = 20.
Answer = 48+32+20 = 100.
Given data:
no.of students 8 yrs exact = 48.
no.of students above 8 yrs = 2/3 of 48 = 32.
no.of students below 8 yrs = 20.
Answer = 48+32+20 = 100.
VR Chowdary said:
1 decade ago
8< = 20.
8 = 48.
8>90(2/3)*48 = 32.
Total students = 20+48+32 = 100.
8 = 48.
8>90(2/3)*48 = 32.
Total students = 20+48+32 = 100.
Rupali said:
1 decade ago
Below 8 + equal to 8 + above 8 = total.
20%x + 48 + 2/3*48 = x.
80x = 8000.
x = 100. ANSWER.
20%x + 48 + 2/3*48 = x.
80x = 8000.
x = 100. ANSWER.
Robin Loomba said:
1 decade ago
Total number of students = x.
According to the condition:
20% of student below 8 years + 48 (8 years student) + (2/3)*48 above 8 years = x (total number of students).
20% of x + 48 + 32 = x.
(20/100)*x + 80 = x.
80 = x-x/5.
80 = 4x/5.
x = 100.
According to the condition:
20% of student below 8 years + 48 (8 years student) + (2/3)*48 above 8 years = x (total number of students).
20% of x + 48 + 32 = x.
(20/100)*x + 80 = x.
80 = x-x/5.
80 = 4x/5.
x = 100.
Ashish jain said:
1 decade ago
Why 48 is added?
Sankarshan said:
1 decade ago
What ever may be the % of students below 8 years,
Let x be the no of students below 8 years.
So ,
(2/3)x = 48;
x = (48*3)/2;
x = 72;
So total no of students = 72+48 = 120.
Why this answer is wrong?
Let x be the no of students below 8 years.
So ,
(2/3)x = 48;
x = (48*3)/2;
x = 72;
So total no of students = 72+48 = 120.
Why this answer is wrong?
Pinal patel said:
1 decade ago
Why 48+2/3 of 48?
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