Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
 Required percentage = |
 |
50 | x 100 |  % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
144 comments Page 4 of 15.
Manju said:
1 decade ago
Just apply yours common sense if get marks in percentages ie (acquired marks/total marks) right, then you will get result.
Vijay said:
1 decade ago
Total batsman score = 110.
Include 3*four and 8*sixes.
=12+48.
Include of six and four = 60.
Total score-sixes and fours = 110-60 = 50.
Percentage = Remaining without six and fours/total score**100.
= 110/50*100.
= 11/5*100.
= 1100/5.
= 45*5/11.
Include 3*four and 8*sixes.
=12+48.
Include of six and four = 60.
Total score-sixes and fours = 110-60 = 50.
Percentage = Remaining without six and fours/total score**100.
= 110/50*100.
= 11/5*100.
= 1100/5.
= 45*5/11.
Prem said:
1 decade ago
3*4=12,
8*6= 48,
48+12=60.
Total run b/w the wickets 110 - 60 = 50.
Therefore %= 50/110* 100 = 45.454545.
8*6= 48,
48+12=60.
Total run b/w the wickets 110 - 60 = 50.
Therefore %= 50/110* 100 = 45.454545.
Sumanth said:
1 decade ago
How 5 came in the last equation .i,e; 45*5/11?
Naveen said:
1 decade ago
11)500(45
495
___
5
Quotient*(remainder/division) = 45*5/11.
495
___
5
Quotient*(remainder/division) = 45*5/11.
Vikrant raushan said:
1 decade ago
@Jay. Answer to wheat problem.
Let x kg of 4.5 and y kg of 5.25 Rs variety.
So,
4.5x+5.25y = 5(x+y).
on solving we get,
0.25y = 0.5x.
(x/y) = 25/50.
x:y = 1:2.
Let x kg of 4.5 and y kg of 5.25 Rs variety.
So,
4.5x+5.25y = 5(x+y).
on solving we get,
0.25y = 0.5x.
(x/y) = 25/50.
x:y = 1:2.
Tejesh said:
1 decade ago
Total runs = 110.
Covered by = 60.
110-60 = 50.
So 50/1100*100.
45*5/11.
Covered by = 60.
110-60 = 50.
So 50/1100*100.
45*5/11.
Ash said:
1 decade ago
500/11
Hence we can write 500/11 = 45*5/11.
45
-----
11 ! 500
! 44
!----
60
55
-----
5
Hence we can write 500/11 = 45*5/11.
Rahul said:
1 decade ago
Any one explain how 45 is came?
Arulsevi said:
1 decade ago
Total runs = 110.
Runs got by boundary & sixes = 60//[4x3 + 8x6].
Runs got by wickets = 110-60 = 50.
They are asking what percentage 60 is what % of 110.
So, x% of 110 = 60.
x*110/100 = 60.
x = option B.
Runs got by boundary & sixes = 60//[4x3 + 8x6].
Runs got by wickets = 110-60 = 50.
They are asking what percentage 60 is what % of 110.
So, x% of 110 = 60.
x*110/100 = 60.
x = option B.
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