Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
 Required percentage = |
 |
50 | x 100 |  % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
139 comments Page 1 of 14.
Sana said:
1 week ago
See follow like this:
Given that;
Total runs = 110,
Total six = 8 * 6 = 48,
Boundaries = 4 * 3 = 12,
110-48 + 12 = 50.
Now find
110= 100%.
50=?
50/110 * 100 = 45 5/11.
Given that;
Total runs = 110,
Total six = 8 * 6 = 48,
Boundaries = 4 * 3 = 12,
110-48 + 12 = 50.
Now find
110= 100%.
50=?
50/110 * 100 = 45 5/11.
(1)
Sybil said:
4 months ago
why here we can't use the rule:x% of y= y% of x?
Anyone, please explain to me.
Anyone, please explain to me.
(6)
Lavanya Ayyadhurai said:
5 months ago
Can anyone please elaborate this? I can't get this clearly
(14)
Dhileep D said:
6 months ago
Actually, it converts from 500/11 to 45*(5/11) to a mixed fraction by quotient* remainder/divisor.
For eg: By dividing 500/11 we get quotient =45, remainder=5 divisor =11.
Then we form 45* (5\11).
For eg: By dividing 500/11 we get quotient =45, remainder=5 divisor =11.
Then we form 45* (5\11).
(24)
Gayatri Peesa said:
9 months ago
I am not understanding this. Someone please explain to me.
(22)
Harish Mp said:
9 months ago
It was so helpful. Thanks all for the explanation.
(12)
Madhuwala said:
2 years ago
Total run = 110.
Eight sixes = 48 run,
Three boundaries = 12run,
So, running between wicket=(110-48+12) = 50.
therefore, percentage of 50 run =(50/110)*100 = 45 * 5/11.
Eight sixes = 48 run,
Three boundaries = 12run,
So, running between wicket=(110-48+12) = 50.
therefore, percentage of 50 run =(50/110)*100 = 45 * 5/11.
(73)
Rajjo said:
2 years ago
How to find the ration? I am not understanding the concept. Anyone, Please help me to get it.
(31)
A SANTHI said:
2 years ago
The total run is - 110
Boundaries(4's) - 3.
Sixes- 8.
Therefore, (4*3)+(6*8)= 12+48 = 60.
Running between the wickets means (1's or 2's which they get)
Therefore need to know the running b/w wickets:
110 - 60 =50.
And the percentage for running b/w wickets is;
= 50/110 * 100,
= 500/11,
= 45 * 5/11%.
Boundaries(4's) - 3.
Sixes- 8.
Therefore, (4*3)+(6*8)= 12+48 = 60.
Running between the wickets means (1's or 2's which they get)
Therefore need to know the running b/w wickets:
110 - 60 =50.
And the percentage for running b/w wickets is;
= 50/110 * 100,
= 500/11,
= 45 * 5/11%.
(68)
Ashu said:
2 years ago
@Sanchita.
Here, 1 six have 6 runs and 1 boundary means 4 runs.
Here, 1 six have 6 runs and 1 boundary means 4 runs.
(18)
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