Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
Required percentage = |
![]() |
50 | x 100 | % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
153 comments Page 3 of 16.
NIRMAL S said:
4 years ago
The question is very simple.
Out of 110 Runs, he scored 60 runs by hitting the boundaries. Also, it is mentioned to calculate what percentage of total runs will he score by running between the wickets.
So,
(x/100)*110 = 50,
Now x = (50*100)/110.
Out of 110 Runs, he scored 60 runs by hitting the boundaries. Also, it is mentioned to calculate what percentage of total runs will he score by running between the wickets.
So,
(x/100)*110 = 50,
Now x = (50*100)/110.
(5)
Prasanna said:
5 years ago
Total runs : 110
boundaries :3 ie 3 * 4=12.---> 12 +48
six : 8 ie 8*6 =48 ---->=60.
= total run -addition of 4 and 6
= 110 -60 ie = 50
= 50/100 *100. ie 5000/110.
ie. 500/11(put in division method),
then 11 is divisor 5 is remainder 45 is the quotient,
45 * 5/11.
boundaries :3 ie 3 * 4=12.---> 12 +48
six : 8 ie 8*6 =48 ---->=60.
= total run -addition of 4 and 6
= 110 -60 ie = 50
= 50/100 *100. ie 5000/110.
ie. 500/11(put in division method),
then 11 is divisor 5 is remainder 45 is the quotient,
45 * 5/11.
(4)
Nisha kadam said:
5 years ago
Here, Why we subtract 60 from 110? Please explain me.
(4)
Hasini said:
5 months ago
How 5/11 come at the end? Please explain to me.
(4)
Manikandan said:
5 years ago
Total runs =110.
Boundaries means (4)=>so,
Qus:3 boundaries =3*4=12.
Sixes(6)=>so,
Qus:8 sixes = 8*6=48.
So, boundary + sixes = 12 + 48 = 60.
The, 60 runs is only boundaries and sixes.
But, the question was running b/w the wickets (only scores the runs in running ).
So, total - (boundaries &sixes) = running runs.
So, 110(total) - 60(boundaries &sixes) = 50(running runs).
Here, it is asked percentage :
So, running runs/total *100 = ans.
So, 50/110*100 = 500/11,
And the answer is 45*5/11.
Boundaries means (4)=>so,
Qus:3 boundaries =3*4=12.
Sixes(6)=>so,
Qus:8 sixes = 8*6=48.
So, boundary + sixes = 12 + 48 = 60.
The, 60 runs is only boundaries and sixes.
But, the question was running b/w the wickets (only scores the runs in running ).
So, total - (boundaries &sixes) = running runs.
So, 110(total) - 60(boundaries &sixes) = 50(running runs).
Here, it is asked percentage :
So, running runs/total *100 = ans.
So, 50/110*100 = 500/11,
And the answer is 45*5/11.
(3)
Lavanya said:
6 months ago
Total score = 110,
3 * 4 = 12,
8 * 6 = 48.
Total score - six and four = 110 - 60 = 50,
Percentage = 50/1100 * 100,
= 45(5/11).
3 * 4 = 12,
8 * 6 = 48.
Total score - six and four = 110 - 60 = 50,
Percentage = 50/1100 * 100,
= 45(5/11).
(2)
Aniket said:
4 months ago
Given that;
Total runs = 110,
Total six = 8 * 6 = 48,
Boundaries = 4 * 3 = 12,
110 - 48 + 12 = 50,
To find a percentage,
= (50/110) * 100
= 500/11.
Now 45 * 11 = 495,
Mixed fraction form;
= 45 *(5/11).
Total runs = 110,
Total six = 8 * 6 = 48,
Boundaries = 4 * 3 = 12,
110 - 48 + 12 = 50,
To find a percentage,
= (50/110) * 100
= 500/11.
Now 45 * 11 = 495,
Mixed fraction form;
= 45 *(5/11).
(2)
Anonymous said:
4 months ago
Total Runs 110.
3 boundaries = 3 * 4 = 12.
8 * 6 = 48,
12 + 48 = 60.
Between wickets is 110-60 = 50.
Now they have asked me to find the % of 110 = 50
Simply add 2 zeros to 50 and divide by 110
eg: %10 of x =a.
=>a00/10 find x.
eg: x% of 100 = a.
=>a00/100 find x.
x% of 110 = 50,
=>5000/110= 45.45.
3 boundaries = 3 * 4 = 12.
8 * 6 = 48,
12 + 48 = 60.
Between wickets is 110-60 = 50.
Now they have asked me to find the % of 110 = 50
Simply add 2 zeros to 50 and divide by 110
eg: %10 of x =a.
=>a00/10 find x.
eg: x% of 100 = a.
=>a00/100 find x.
x% of 110 = 50,
=>5000/110= 45.45.
(2)
Ashwanth Sa said:
4 months ago
Yes, the 45(5/11) is the right answer.
(2)
Gaurav said:
3 months ago
@All.
Explanation: out of 110 runs with bound and 8 sixes : 3 boundaries + 8 sixes = 60 runs with bound and 8sixes rest are runs with running between wickets.
110-60 = 50 (now they ask for the percentage for 50 with 110), that is 50% of 110, then
50/100 * 110 = 45.4% which is the correct answer.
Explanation: out of 110 runs with bound and 8 sixes : 3 boundaries + 8 sixes = 60 runs with bound and 8sixes rest are runs with running between wickets.
110-60 = 50 (now they ask for the percentage for 50 with 110), that is 50% of 110, then
50/100 * 110 = 45.4% which is the correct answer.
(2)
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Required percentage =
% = 45