Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 1)
1.
A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option
Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
 Required percentage = |
 |
50 | x 100 |  % = 45 |
5 | % |
| 110 | 11 |
Video Explanation: https://youtu.be/X2zTnABqEHU
Discussion:
157 comments Page 3 of 16.
Hemanth said:
3 months ago
It's a good session. Thanks to all for explaining it in detail.
(8)
Aniket said:
9 months ago
Given that;
Total runs = 110,
Total six = 8 * 6 = 48,
Boundaries = 4 * 3 = 12,
110 - 48 + 12 = 50,
To find a percentage,
= (50/110) * 100
= 500/11.
Now 45 * 11 = 495,
Mixed fraction form;
= 45 *(5/11).
Total runs = 110,
Total six = 8 * 6 = 48,
Boundaries = 4 * 3 = 12,
110 - 48 + 12 = 50,
To find a percentage,
= (50/110) * 100
= 500/11.
Now 45 * 11 = 495,
Mixed fraction form;
= 45 *(5/11).
(7)
Bfdg said:
4 years ago
Out of 110 Runs, he scored 60 runs by hitting the boundaries. Also, it is mentioned to calculate what percentage of total runs will he score by running between the wickets.
Am I right? Anyone, Please clarify.
Am I right? Anyone, Please clarify.
(6)
Praphul P said:
1 year ago
@Kiraa.
Hey, it is not 50/100, it's 50/110.
Because 110 is the total.
Hey, it is not 50/100, it's 50/110.
Because 110 is the total.
(6)
NIRMAL S said:
5 years ago
The question is very simple.
Out of 110 Runs, he scored 60 runs by hitting the boundaries. Also, it is mentioned to calculate what percentage of total runs will he score by running between the wickets.
So,
(x/100)*110 = 50,
Now x = (50*100)/110.
Out of 110 Runs, he scored 60 runs by hitting the boundaries. Also, it is mentioned to calculate what percentage of total runs will he score by running between the wickets.
So,
(x/100)*110 = 50,
Now x = (50*100)/110.
(5)
Kannan said:
1 week ago
Hi guys.
Total runs = 110.
4's = 3 ( 4*3 = 12).
6's = 8 ( 6*8 = 48).
12 + 48 = 60.
Running between wicker = 110 - 60 = 50.
50/ 110 * 100 = 500/11 = 45 (5/11).
Total runs = 110.
4's = 3 ( 4*3 = 12).
6's = 8 ( 6*8 = 48).
12 + 48 = 60.
Running between wicker = 110 - 60 = 50.
50/ 110 * 100 = 500/11 = 45 (5/11).
(5)
Prasanna said:
5 years ago
Total runs : 110
boundaries :3 ie 3 * 4=12.---> 12 +48
six : 8 ie 8*6 =48 ---->=60.
= total run -addition of 4 and 6
= 110 -60 ie = 50
= 50/100 *100. ie 5000/110.
ie. 500/11(put in division method),
then 11 is divisor 5 is remainder 45 is the quotient,
45 * 5/11.
boundaries :3 ie 3 * 4=12.---> 12 +48
six : 8 ie 8*6 =48 ---->=60.
= total run -addition of 4 and 6
= 110 -60 ie = 50
= 50/100 *100. ie 5000/110.
ie. 500/11(put in division method),
then 11 is divisor 5 is remainder 45 is the quotient,
45 * 5/11.
(4)
Nisha kadam said:
5 years ago
Here, Why we subtract 60 from 110? Please explain me.
(4)
Hasini said:
10 months ago
How 5/11 come at the end? Please explain to me.
(4)
Anonymous said:
8 months ago
Total Runs 110.
3 boundaries = 3 * 4 = 12.
8 * 6 = 48,
12 + 48 = 60.
Between wickets is 110-60 = 50.
Now they have asked me to find the % of 110 = 50
Simply add 2 zeros to 50 and divide by 110
eg: %10 of x =a.
=>a00/10 find x.
eg: x% of 100 = a.
=>a00/100 find x.
x% of 110 = 50,
=>5000/110= 45.45.
3 boundaries = 3 * 4 = 12.
8 * 6 = 48,
12 + 48 = 60.
Between wickets is 110-60 = 50.
Now they have asked me to find the % of 110 = 50
Simply add 2 zeros to 50 and divide by 110
eg: %10 of x =a.
=>a00/10 find x.
eg: x% of 100 = a.
=>a00/100 find x.
x% of 110 = 50,
=>5000/110= 45.45.
(4)
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