Aptitude - Percentage - Discussion

Total runs 110.

3 boundaries=3*4=12.
8 sixes =8*6=48.

Total score = 110-(12+48)
=110-60.
=50 total runs.

Percentage =50/110 * 100,
= 500/11.
= 45.45 mixed fraction lo rayaga 45*5/11.

why here we can't use the rule:x% of y= y% of x?

Anyone, please explain to me.

Total run = 110.

And runs scored by boundaries and sixes are (3*4=12)+ (8*6=48) = 60,
Rest scores made by running = 110 - 60 = 50 runs.
So percentage of running's score = (running's score / total Score )*100.
= (50/110)*100 = (5/11)*100.
= 500/11,
=> (45/1)+(5/11).
i.e option (B).

All the given explanations are very helpful for understanding the solution. Thanks all.

Total score : 110.

Three boundaries, that is 3 * 4 =12.
8 six , that is 8 * 6 = 48,

The score He runs between the wickets means.

reduce the above-mentioned values like boundaries and sixes from the total score, that is

110 - 12+48 = 50.

Percentage of 50 runs equal to
50/110 * 100%.
5000/110.

= 45.45.
.45 into fractional form.
Follow the following steps.
.45 to 45.

Then 45/100 here we taking 45/100 since there is two decimal points here
45/100 = 9/11.
50/110 * 100 =45 * 9/11.

The approximate answer from options is 45(5/11).

How 6 and 4 came here? Please explain.

Total runs = 110.
Total runs from boundaries and sixes = 8 * 6 + 3 * 4 = 60,
Runs made by running between the wickets = 110-60 = 50,
Percentage of run made by running between the wickets = (50/110 * 100)% = 45.45%.
Correct Answer : (C)

Hay guys. I have a confusion that how the (50/100) *100=45*5/11 ? Will you please explain to me.

How 4 came here? Please, someone, explain to me.

3 boundaries = 4 * 3 = 12.
8 sixes = 8 * 6 = 48.
Total score = 110.

The score without boundaries btw wickets = [(110 - (12+48))/110] * 100 = (45+5/11)%.