Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
93 comments Page 9 of 10.
Bhavna said:
1 decade ago
Thanks shivani.
Shivani said:
1 decade ago
@ jagadeesh and reeta
1 decade = 10 years ........
here we need the average of percent rise ...
here the increment in percentage for 10 years is 50
so average = 50 / 10
= 5
got it?? ....
1 decade = 10 years ........
here we need the average of percent rise ...
here the increment in percentage for 10 years is 50
so average = 50 / 10
= 5
got it?? ....
Suman said:
1 decade ago
Thanku Naren you gave a very shortcut method.
Reeta said:
1 decade ago
What is required average? Why it is divided by 10?
Jagadeesh said:
1 decade ago
What is required average? Why it is divided by 10?
Pavan said:
1 decade ago
Nice Muthupazhani.
Muthupazhani said:
1 decade ago
No need to do these much calculation its very simple
consider his salary is X then
give 10% of his salary is 30rs from this
x*10/100=30
x/10=30
x=300
consider his salary is X then
give 10% of his salary is 30rs from this
x*10/100=30
x/10=30
x=300
Naren said:
1 decade ago
Ya vijay is correct....
Let his expenses 20+60+10=90
Remaining money 30, means 10%=30, Then 100%=300
Let his expenses 20+60+10=90
Remaining money 30, means 10%=30, Then 100%=300
Vishnu said:
1 decade ago
Ya vinay is right.
Let his salary is x. let us consider only expenses (20/100)*x+(60/100)*x+(10/100)*x are expenses.
in problem it given that if we subtract all expenses from salary,he remained with 30rs which used for education so,
x-((20/100)*x+(60/100)*x+(10/100)*x)=30
(100x-(20x+60x+10x))/100=30
100x-90x=3000
10x=3000
x=300
so vijay is right.......of course me tooooo.
Let his salary is x. let us consider only expenses (20/100)*x+(60/100)*x+(10/100)*x are expenses.
in problem it given that if we subtract all expenses from salary,he remained with 30rs which used for education so,
x-((20/100)*x+(60/100)*x+(10/100)*x)=30
(100x-(20x+60x+10x))/100=30
100x-90x=3000
10x=3000
x=300
so vijay is right.......of course me tooooo.
Rahul said:
1 decade ago
@vijay.
Ya you are right vijay. Watt aparna did is wrong.
Ya you are right vijay. Watt aparna did is wrong.
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