Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
96 comments Page 9 of 10.
Niks said:
1 decade ago
By the way aparna's answer to manishas question is right. How can you reuse the total amount be it rs 100 or x again and again. Plus I have seen a lot of similar examples solved it in aparnas way. Check out for these kind of examples in MBA aptitude books.
Bluespark said:
1 decade ago
@ak123
%increase=(increase*100)/year its a formula since u r finding the increase % of 175000, yr=175000
%increase=(increase*100)/year its a formula since u r finding the increase % of 175000, yr=175000
Ak123 said:
1 decade ago
Why is 87,000 divided by 1,75,000? can someone explain.
Bhavna said:
1 decade ago
Thanks shivani.
(1)
Shivani said:
1 decade ago
@ jagadeesh and reeta
1 decade = 10 years ........
here we need the average of percent rise ...
here the increment in percentage for 10 years is 50
so average = 50 / 10
= 5
got it?? ....
1 decade = 10 years ........
here we need the average of percent rise ...
here the increment in percentage for 10 years is 50
so average = 50 / 10
= 5
got it?? ....
Suman said:
1 decade ago
Thanku Naren you gave a very shortcut method.
Reeta said:
1 decade ago
What is required average? Why it is divided by 10?
Jagadeesh said:
1 decade ago
What is required average? Why it is divided by 10?
Pavan said:
1 decade ago
Nice Muthupazhani.
(1)
Muthupazhani said:
1 decade ago
No need to do these much calculation its very simple
consider his salary is X then
give 10% of his salary is 30rs from this
x*10/100=30
x/10=30
x=300
consider his salary is X then
give 10% of his salary is 30rs from this
x*10/100=30
x/10=30
x=300
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