Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Answer: Option
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

Discussion:
93 comments Page 10 of 10.

Vijay said:   1 decade ago
@aparna you may be wrong becoz...

suppose his salary is x Rs.
then 20% of his x for rent=20/100*x = 20x/100...1
60% of his x for living expanses = 60x/100...2
10% of his x for LIC = 10x/100...3
30 Rs on education he spent

then we can write (20x/100)+(60x/100)+(10x/100)+30 = x
solve this you get x = 300
for check you put x value in all equations 1,2, 3 and add them with 30
you get total salary as 300

Aparna said:   1 decade ago
@manisha
suppose his salary is Rs.100
20% of 100=20
100-20=80
60% of 80=48
80-48=32
10% of 32=3.2
32-3.2=28.8

hence
28.8 = 30
100 =?

we get
104.16
hence his salary is Rs.104.16

Manisha said:   1 decade ago
how to solve this question if 20% of man's salary is paid as rent, 60%are his living expanses, and 10% is paid in L.I.C. if he spends remaining Rs. 30 on the education of the children, find his salary.
(1)


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