Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Answer: Option
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

Discussion:
93 comments Page 7 of 10.

Sneha said:   10 years ago
May be it is:

a-0.25 x = c.
b-0.20 x = c.

a-0.25 x = b-0.20 x.
a-0.45 x = b.
a is 45% greater than b.

Shashi said:   1 decade ago
Dear, @Anil.

What is the third number?

Saravanan said:   1 decade ago
How to say it's 10 years difference?

Anil said:   1 decade ago
Two numbers are respectively 25% and 20% more than of third. What percentage is the first of second. Could you solve this problem any one?

Aparna said:   1 decade ago
How 50/10 came in the last step. Can anyone help me to understand?

Dinesh said:   1 decade ago
Dear @Manisha you can solve that problem very simply.

Add all the expenses so 20+60+10 = 90.

Out of 100% 90% spending on his expenses so 100-90 = 10.

Let the salary be x.

10% of x = 30.
10/100*x = 30 we get.

1/10*x = 30.
So x = 300.

Yatender said:   1 decade ago
Most of them are wrong because firstly we use our original salary then 20%of that salary=remaining and 60% of that remaining and so on. @Aparna is right.

Sunil vishwakarma said:   1 decade ago
10 is because there is formula of 2 years, p(1+r/100)^t, where t is for next 2 year, is 2*5 = 10.

Mahi said:   1 decade ago
Why we use 10 here?

Sunil said:   1 decade ago
1,20,000 is the right answer.
138915 = X(1+5/100)^(10).
Calculate X = 1,20,000.


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