Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = | ![]() |
87500 | x 100 | % = 50%. |
| 175000 |
Required average = |
![]() |
50 | % = 5%. |
| 10 |
Discussion:
96 comments Page 5 of 10.
Nikhil dasari said:
9 years ago
We can also solve with options.
A) 4.37 % 175000 = 7647.5.
So decade means 10 year.
multiply 10*7647.5= 76475.
and add the multiply result with the 175000.
i.e)76475+175000 =2514755% 17500.
So it's not matching.
B) 5% 175000 = 8750.
so decade means 10 year.
multiply 10*8750= 87500.
and add the multiply result with the 175000.
i.e)87500+175000 = 262500.
Its right so answer is B.
A) 4.37 % 175000 = 7647.5.
So decade means 10 year.
multiply 10*7647.5= 76475.
and add the multiply result with the 175000.
i.e)76475+175000 =2514755% 17500.
So it's not matching.
B) 5% 175000 = 8750.
so decade means 10 year.
multiply 10*8750= 87500.
and add the multiply result with the 175000.
i.e)87500+175000 = 262500.
Its right so answer is B.
Sankarilakshmi said:
9 years ago
Hi @Jayakumar s
let the total number of votes = x
no.of votes cast = 75% of x
The valid votes = 98% of (no.of votes cast)
i.e 98% of (75% of x) (here 2% is invalid so (100-2)%=98%)
Then (A candidate got 75% of valid votes =9261)
75% of (98% of (75% of x) = > 75/100 * 98/100 *75/100 * x =9261.
= > (9261*100*100*100) / (75*98*75),
= > 9261000000 / 551250,
= >16800.
let the total number of votes = x
no.of votes cast = 75% of x
The valid votes = 98% of (no.of votes cast)
i.e 98% of (75% of x) (here 2% is invalid so (100-2)%=98%)
Then (A candidate got 75% of valid votes =9261)
75% of (98% of (75% of x) = > 75/100 * 98/100 *75/100 * x =9261.
= > (9261*100*100*100) / (75*98*75),
= > 9261000000 / 551250,
= >16800.
Jayakumar s said:
9 years ago
In an election between two candidates, 75% of the voter's caste their votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of votes enrolled in that election.
Can anyone solve this?
Can anyone solve this?
Krishnam raju said:
9 years ago
percentage increase = (increased quantity/initial quantity) * 100.
As given above problem.
Increased quantity = 262500 - 17500.
= 87500
Percentage increase = (87500/175000) * 100.
= 50% per decade means for 10 years.
Per one year = 50/10 = 5%.
As given above problem.
Increased quantity = 262500 - 17500.
= 87500
Percentage increase = (87500/175000) * 100.
= 50% per decade means for 10 years.
Per one year = 50/10 = 5%.
Anil said:
9 years ago
Population in 2001 = 138915
Population in 1998 was = 138915 * 100/105 * 100/105 * 100/105 = 1,20,000.
Had it given the population in 1998 = 1,20,000 then what will be the population in 2001, if it increases @5% PA.
The solution would be = 1,20,000 * 105/100 * 105/100 * 105/100 = 138915 (population in 2001).
Population in 1998 was = 138915 * 100/105 * 100/105 * 100/105 = 1,20,000.
Had it given the population in 1998 = 1,20,000 then what will be the population in 2001, if it increases @5% PA.
The solution would be = 1,20,000 * 105/100 * 105/100 * 105/100 = 138915 (population in 2001).
Arisha said:
9 years ago
How (50/10)%?
Shru said:
9 years ago
Guys it's very simple, here they used the formula for % change that is =difference in % ÷ initial value * 100.
Satwika said:
9 years ago
Why should we take 17,5000 in denominator why not 26,25000?
Mohsin said:
9 years ago
10% is equal to 30.
While 100% is equal to?
Then,
30 * 100/10 = 300.
While 100% is equal to?
Then,
30 * 100/10 = 300.
Ann said:
9 years ago
I think the official answer is wrong : if you increase a population of 175,000 by 5% each year during 10 years it becomes more than 262,500.
Proof 175,000 * (1.05 ^ 10) = 285'056.56 that's more then 262,500!
So it should be less than 5%.
Right answer : ( (262,500/175,000) ^ 0.1) - 1 = 4.137974%.
So, A mus be the right choice.
Proof 175,000 * (1.05 ^ 10) = 285'056.56 that's more then 262,500!
So it should be less than 5%.
Right answer : ( (262,500/175,000) ^ 0.1) - 1 = 4.137974%.
So, A mus be the right choice.
(2)
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% = 50%.
Required average =