Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
93 comments Page 5 of 10.
Krishnam raju said:
9 years ago
percentage increase = (increased quantity/initial quantity) * 100.
As given above problem.
Increased quantity = 262500 - 17500.
= 87500
Percentage increase = (87500/175000) * 100.
= 50% per decade means for 10 years.
Per one year = 50/10 = 5%.
As given above problem.
Increased quantity = 262500 - 17500.
= 87500
Percentage increase = (87500/175000) * 100.
= 50% per decade means for 10 years.
Per one year = 50/10 = 5%.
Anil said:
9 years ago
Population in 2001 = 138915
Population in 1998 was = 138915 * 100/105 * 100/105 * 100/105 = 1,20,000.
Had it given the population in 1998 = 1,20,000 then what will be the population in 2001, if it increases @5% PA.
The solution would be = 1,20,000 * 105/100 * 105/100 * 105/100 = 138915 (population in 2001).
Population in 1998 was = 138915 * 100/105 * 100/105 * 100/105 = 1,20,000.
Had it given the population in 1998 = 1,20,000 then what will be the population in 2001, if it increases @5% PA.
The solution would be = 1,20,000 * 105/100 * 105/100 * 105/100 = 138915 (population in 2001).
Arisha said:
9 years ago
How (50/10)%?
Shru said:
9 years ago
Guys it's very simple, here they used the formula for % change that is =difference in % ÷ initial value * 100.
Satwika said:
9 years ago
Why should we take 17,5000 in denominator why not 26,25000?
Mohsin said:
9 years ago
10% is equal to 30.
While 100% is equal to?
Then,
30 * 100/10 = 300.
While 100% is equal to?
Then,
30 * 100/10 = 300.
Ann said:
9 years ago
I think the official answer is wrong : if you increase a population of 175,000 by 5% each year during 10 years it becomes more than 262,500.
Proof 175,000 * (1.05 ^ 10) = 285'056.56 that's more then 262,500!
So it should be less than 5%.
Right answer : ( (262,500/175,000) ^ 0.1) - 1 = 4.137974%.
So, A mus be the right choice.
Proof 175,000 * (1.05 ^ 10) = 285'056.56 that's more then 262,500!
So it should be less than 5%.
Right answer : ( (262,500/175,000) ^ 0.1) - 1 = 4.137974%.
So, A mus be the right choice.
(2)
Surya said:
9 years ago
Decade means?
Sreekanth said:
9 years ago
Anyone explain how 50/10?
Angelo said:
9 years ago
What is the answer, if the population of the town is increased by 5% annually. If its population in 2001 was 138915. Then What was it in 1998?
Please anyone solve this.
Please anyone solve this.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers