Aptitude - Numbers - Discussion

Let the given num is x.
And quotient is P.

Now according to the formula, x= 357P+39 ........(i).

Again, when the same number is divided by 17, let then quotient = Q and the remainder = R
then, x = 17Q+R ...........(ii).

Now, comparing (i) & (ii) we get,
357P+39 = 17Q+R ...........(iii)
Let P=1, then, 357+39 = 17Q+R
That means, 396 = 17Q+R
Now if we divide 396 by 17, we get
396= 17 (23) + 5 ..........(iv)

Now comparing, (iii) & (iv), R=5.
So the required number is 5.

357/17=21. So if 357 into a number leaves 39 as a remainder, that means that if you take (21*17) into the number (same as 357), it leaves 39 left over. How many times will 17 alone go into that remaining 39? Twice, since 17*2 = 34. That leaves a remainder of 5.

Easy way, suppose the no.is x A/C to ques. on dividing a no by 357 it gives 39 as a remainder, think when it gives remainder as a 39?

When x value is 396(i.e. 357+39=396)so x =396. Now if you divide that no(396)by 17 it will gives 5 as remainder.

Formula :
Dividend = divisor * quotient + remainder.
Let dividend be n.
n=357q+39 ---> (1)
n=17q+r --> (2).
Compare (2)with (1)
So (1)should be of multiple of 17.
n = 17 * 11q + 34 + 5
n = 17(11q + 1) + 5 ---> (3).
Compare 3 with (2).
And r=5.

Please solve this problem in an easy way and explain the answer.

On dividing a certain number by 342, we get 47 as a reminder. If the same number is divided by 18, what will be the reminder?

On this type of questions you do.

Let x be the number

Given x/357=39 (remainder).

So you will divide the remainder from the next no (17).

So the answer is 39/17=5 as a remainder(answer).

We will first try to relate 357 and 17.

When we divide 357 by 17 reminder is 0.
That means 17 is a multiple of 357,
Hence we divide 39 by 17 reminder 5 will come.
That's the answer 5.

It's not working for all problems.

Apply the formula for this:

When a number is divided by 32 it leaves reminder of 21. What will be the remainder when the number is divided by 18?

If I change the question like:

A number when divided by 17 leaves remainder 5 then what remainder would be obtained by dividing the same number by 357?

Can anyone answer me?

FORMULA :

Dividend=divisor * quotient + remainder.

Here, we ca use;
Dividend = divisor + remainder.
x = 357 + 39,
x = 396.
AB 396 DIVIDED by 17.
Then the remainder 5.