# Aptitude - Numbers

Exercise : Numbers - General Questions

- Numbers - Formulas
- Numbers - General Questions

41.

On dividing a number by 357, we get 39 as remainder. On dividing the same number 17, what will be the remainder ?

Answer: Option

Explanation:

Let *x* be the number and *y* be the quotient. Then,

*x* = 357 x *y* + 39

= (17 x 21 x *y*) + (17 x 2) + 5

= 17 x (21*y* + 2) + 5)

Required remainder = 5.

42.

If the product 4864 x 9 P 2 is divisible by 12, then the value of P is:

Answer: Option

Explanation:

Clearly, 4864 is divisible by 4.

So, 9P2 must be divisible by 3. So, (9 + P + 2) must be divisible by 3.

P = 1.

43.

Which one of the following is the common factor of (47

^{43}+ 43^{43}) and (47^{47}+ 43^{47}) ?Answer: Option

Explanation:

When *n* is odd, (*x*^{n} + *a*^{n}) is always divisible by (*x* + *a*).

Each one of (47^{43} + 43^{43}) and (47^{47} + 43^{47}) is divisible by (47 + 43).

44.

-84 x 29 + 365 = ?

Answer: Option

Explanation:

Given Exp. | = -84 x (30 - 1) + 365 |

= -(84 x 30) + 84 + 365 | |

= -2520 + 449 | |

= -2071 |

45.

A number when divided by 296 leaves 75 as remainder. When the same number is divided by 37, the remainder will be:

Answer: Option

Explanation:

Let *x* = 296*q* + 75

= (37 x 8*q* + 37 x 2) + 1

= 37 (8*q* + 2) + 1

Thus, when the number is divided by 37, the remainder is 1.

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