Aptitude - Numbers - Discussion

In the previous example we subtract the remainder from divisor and the result is taken as the required number.
But in this example we take the remainder as a required number.
Why?.. Why this difference?..

This is because in the previous eg. If we substract 29 from the dividend then 13601 will be exactly divisble by 87.

The Actual rule is:

When Remainder < Divisor/2 (half of divisor) then answer will be dividend - remainder = answer.

and

When Remainder > Divisor/2 (half of divisor) then answer will be dividend +(divisor - remainder)= answer.

@Soumya.

Thr is no such rule. Please don't confuse others,

In previous question it was asked how mch no should be ADDED. To get it divisible by 6, 4 WAS remainder. So (6-4) should be added.

In this question is asked what no should be subtracted. From 13601 to get it divisible by 87. Required no is the remainder itself.

In previous question remainder coming was 16.

If we add 2 to it then it becomes 18 which can be divided by 6.
or
If we subtract 4 from the 16 it becomes 12 then also it becomes divisible by 6.

Similarly in this question remainder coming is 29.

So, had the number been 29 less than what it is the remainder would be 0 and hence it would be completely divisible by the divisor.

Hence we subtract the remainder.

Alternatively if we add 58 to the dividend then remainder will be 87 then it will be divisible by 87.

The question statement is wrong. Its saying that the what number should be subtracted from 13601, so that the REMAINDER is divisible by 87.

So that the remainder is divisible by 87?

For this question only from answers 87 is divisible by 29 only.

What least number should be subtracted from 86295031 so that the remainder is exactly divisible by 582?

Can anyone answer this question?

In this problem,by subtracting 29 from this number we get 13572.

1 + 3 + 5 + 7+ 2 = 18

And 8 + 7 = 15, 1 + 5 = 6 so 18 is divisible by 6.

If we want to add then divisor-remainder.

If we want to subtract then only remainder.