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Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 50)
Numbers
50.
What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?
23
31
29
37
49
Answer: Option
Explanation:
 87) 13601 (156
     87
     ----
      490
      435
      ----
       551
       522
       ---
        29
       ---
       
 Therefore, the required number = 29.
Discussion:
17 comments Page 1 of 2.
Asds said:   2 years ago
Thanks for explaining @Adi.
(1)
Abinaya Dinesh said:   4 years ago
Check the divisors of 87 which is 1, 3, 29 and itself.

So when subtracting the given number by the options if it is divisible by 3 then we can choose that as a correct option.

13601 - 29 =13572 to check the divisibility of 3 1+3+5+7+2=18.
(10)
Mukund said:   4 years ago
Right thanks @Adi.
(1)
Otem said:   4 years ago
Yes, you're right, thanks @Adi.
(3)
Subro said:   7 years ago
Yes, you are right, I agree with you @Adi.
Supriya said:   7 years ago
Exactly right @Adi.
(2)
Adi said:   8 years ago
The question is wrongly written because they are saying that the REMINDER is divisible by 87. Can anyone tell me that how they are performing the divison0?

In question, they have not mentioned a word of dividing the (subtracted from 13601) this calculation by 87.
(1)
Suraj said:   8 years ago
If we want to add then divisor-remainder.

If we want to subtract then only remainder.
Vijay mittal said:   9 years ago
In this problem,by subtracting 29 from this number we get 13572.

1 + 3 + 5 + 7+ 2 = 18

And 8 + 7 = 15, 1 + 5 = 6 so 18 is divisible by 6.
(2)
Raj said:   9 years ago
What least number should be subtracted from 86295031 so that the remainder is exactly divisible by 582?

Can anyone answer this question?
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