Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 50)
50.
What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?
23
31
29
37
49
Answer: Option
Explanation:
 87) 13601 (156
     87
     ----
      490
      435
      ----
       551
       522
       ---
        29
       ---
       
 Therefore, the required number = 29.        
Discussion:
17 comments Page 2 of 2.

Adi said:   8 years ago
The question is wrongly written because they are saying that the REMINDER is divisible by 87. Can anyone tell me that how they are performing the divison0?

In question, they have not mentioned a word of dividing the (subtracted from 13601) this calculation by 87.
(1)

Supriya said:   7 years ago
Exactly right @Adi.
(2)

Subro said:   7 years ago
Yes, you are right, I agree with you @Adi.

Otem said:   4 years ago
Yes, you're right, thanks @Adi.
(3)

Mukund said:   4 years ago
Right thanks @Adi.
(1)

Abinaya Dinesh said:   4 years ago
Check the divisors of 87 which is 1, 3, 29 and itself.

So when subtracting the given number by the options if it is divisible by 3 then we can choose that as a correct option.

13601 - 29 =13572 to check the divisibility of 3 1+3+5+7+2=18.
(10)

Asds said:   2 years ago
Thanks for explaining @Adi.
(1)


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