Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 8)
8.
The largest 4 digit number exactly divisible by 88 is:
Answer: Option
Explanation:
Largest 4-digit number = 9999
88) 9999 (113
88
----
119
88
----
319
264
---
55
---
Required number = (9999 - 55)
= 9944.
Discussion:
67 comments Page 3 of 7.
Megha said:
8 years ago
9944, 9988, 8888 all three number divisible by 2 and 11, so how we can find the greatest number?
Ramith said:
8 years ago
When 9999/88 = remain 55 how is that 9999/88 = 116.625?
Biswarupa rout said:
7 years ago
Why you take 9999? Please explain.
Shivraj said:
7 years ago
Because, 9999 is largest four digit number, whenever we devide it by 88 reminder remains 55, when we substract 55 from 9999 we get exact number which is divisible by 88 i.e. 9944.
Charan said:
5 years ago
Simple trick to solve.
Take unit digit method.
88 * 88 take unit place and multiple it we get 64. We check the options which option unit place is 4. There is only one option unit digit is 4 ie. Option A.
Take unit digit method.
88 * 88 take unit place and multiple it we get 64. We check the options which option unit place is 4. There is only one option unit digit is 4 ie. Option A.
Sudeshna said:
7 years ago
@Biswarup rout.
A. 4 digit number has Th H T and One's place.
Under each place value, the minimum value we can write is 0 and the maximum value is 9. Hence, if ones, tens, hundred and Thousand all have 9, then 9999 is the largest 4 digit number.
Similarly, largest 5 digits will have 99999 so on and so forth.
The smallest 4 digit will be 1000.
Smallest 5 digit will be 10000.
A. 4 digit number has Th H T and One's place.
Under each place value, the minimum value we can write is 0 and the maximum value is 9. Hence, if ones, tens, hundred and Thousand all have 9, then 9999 is the largest 4 digit number.
Similarly, largest 5 digits will have 99999 so on and so forth.
The smallest 4 digit will be 1000.
Smallest 5 digit will be 10000.
K .srikanth said:
6 years ago
Largest 4 digit number is 9999. In the question they asked what is the largest 4digit number divisible by 88 (just we assume largest number is 9999).
Ruchita said:
6 years ago
Here is an easier method.
First, divide 9999 by 11(9999/11=909).
Then divide 909 by 8 (909/8 = we get 5 reminder).
But 5 is for 909.
909=5.
9999=?.
Then 9099*5/909.
We can get 55 reminder by this easy method.
First, divide 9999 by 11(9999/11=909).
Then divide 909 by 8 (909/8 = we get 5 reminder).
But 5 is for 909.
909=5.
9999=?.
Then 9099*5/909.
We can get 55 reminder by this easy method.
Aarya said:
6 years ago
Because it is the biggest 4 digit number -9999.
Abhishek kumar said:
8 years ago
It is one of the best ways to solve this type of questions that you take4 digit largest number 9999.
Then divide it by 88 but brake 88 in 8*11 then divide 9999 by 11 you will get 99.
Then you will divide it by 8 you will get 5 as remainder then multiple remainders with 11 the total remainder is 55 so 9999-55=9944 is the answer.
9999/8*11=99/8=5*11=55.
9999-55=9944.
Then divide it by 88 but brake 88 in 8*11 then divide 9999 by 11 you will get 99.
Then you will divide it by 8 you will get 5 as remainder then multiple remainders with 11 the total remainder is 55 so 9999-55=9944 is the answer.
9999/8*11=99/8=5*11=55.
9999-55=9944.
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