Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 8)
8.
The largest 4 digit number exactly divisible by 88 is:
Answer: Option
Explanation:
Largest 4-digit number = 9999
88) 9999 (113
88
----
119
88
----
319
264
---
55
---
Required number = (9999 - 55)
= 9944.
Discussion:
67 comments Page 2 of 7.
Darshan Prajapati said:
4 years ago
How it is correct? because above in the example no. 6 method is to split the number & then check the number either diveded by all or not.
And same method if we applied in this example (11*2*4) = 88.
So, 9988 is divided by all 11, 2, & 4.
Please anyone clarify this.
And same method if we applied in this example (11*2*4) = 88.
So, 9988 is divided by all 11, 2, & 4.
Please anyone clarify this.
(3)
Murali goud said:
7 years ago
We can write 88=11*8=11*4*2.
So the 4 digit number must be divisible by all the digits i.e 11,4,2.
But where am I confusing is the number 9988 is divisible by all the numbers i.e 11,4,2 but it is not divisible by 88.
Why? The method is wrong or write? Can anyone suggest?
So the 4 digit number must be divisible by all the digits i.e 11,4,2.
But where am I confusing is the number 9988 is divisible by all the numbers i.e 11,4,2 but it is not divisible by 88.
Why? The method is wrong or write? Can anyone suggest?
(2)
Nantha said:
2 years ago
@Darshan Prajapati.
We should treat the number as 2×4 and not 2, 4.88=11×2^3.
So, it should be divisible by 8 and not just by 4.
We should treat the number as 2×4 and not 2, 4.88=11×2^3.
So, it should be divisible by 8 and not just by 4.
(2)
Chandrika said:
2 months ago
9768 is also divisible by 88, but it is not the largest number.
(1)
Aditya said:
6 years ago
The easiest way to understand this is Euclid's division lemma.
Dividend = divisior * quatient+remainder.
So 9999 = 88 * 113 + 55..
9999-55 = 88 * 113 = 9944 = 9944.
Dividend = divisior * quatient+remainder.
So 9999 = 88 * 113 + 55..
9999-55 = 88 * 113 = 9944 = 9944.
(1)
Pankaj Namekar said:
7 years ago
9988 is the answer because;
88= (11*2*4).
9988 is completely divisible by 88.
88= (11*2*4).
9988 is completely divisible by 88.
(1)
Abhishek kumar said:
8 years ago
It is one of the best ways to solve this type of questions that you take4 digit largest number 9999.
Then divide it by 88 but brake 88 in 8*11 then divide 9999 by 11 you will get 99.
Then you will divide it by 8 you will get 5 as remainder then multiple remainders with 11 the total remainder is 55 so 9999-55=9944 is the answer.
9999/8*11=99/8=5*11=55.
9999-55=9944.
Then divide it by 88 but brake 88 in 8*11 then divide 9999 by 11 you will get 99.
Then you will divide it by 8 you will get 5 as remainder then multiple remainders with 11 the total remainder is 55 so 9999-55=9944 is the answer.
9999/8*11=99/8=5*11=55.
9999-55=9944.
Aditya said:
8 years ago
Is it possible answer is 9876?
Gitanjali said:
8 years ago
What if the question is smallest 4 digit number. I know we need to divide with 1000 but what we'll do after divisions like here it is 9999 - 55, what will be there?
Sowmiya said:
8 years ago
Why we take (9999-55)?
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