IndiaBIX

Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 8)
Numbers
8.
The largest 4 digit number exactly divisible by 88 is:
9944
9768
9988
8888
None of these
Answer: Option
Explanation:
Largest 4-digit number = 9999

 88) 9999 (113
     88
     ----
     119
      88
     ----
      319
      264
      ---
       55
      ---
       
 Required number = (9999 - 55)
                 = 9944.
Discussion:
68 comments Page 7 of 7.
Rakeshnartu@gmail.com said:   10 years ago
Apply divisibility test of 8 for this problem the last three digits should be divisible by 8.
Manyamuma said:   10 years ago
Why can not we do it by splitting the number 88 as 11 * 4 * 2?
Raksha said:   10 years ago
How 9999 is a largest 4 digit number? Please someone help me.
Rohit said:   10 years ago
Becoz in 4 digits number the 9999 is last and largest.
Jayadev sahoo said:   9 years ago
The number is also divisible by 11, 8, then divisible by 88.

All number divisible by 11, 8 expect 9988 then the largest number is 9944.
Shubham Pandey said:   9 years ago
The least number of five digits exactly divisible by 88 is?

Please solve it.
Binit said:   9 years ago
88=11*8.
9944 have three digit number is 944 which is divisible by 8.
and when we substract its attractive number it is =0 so, it is divisible by 11 so it answers.
Abhishek kumar said:   9 years ago
It is one of the best ways to solve this type of questions that you take4 digit largest number 9999.

Then divide it by 88 but brake 88 in 8*11 then divide 9999 by 11 you will get 99.

Then you will divide it by 8 you will get 5 as remainder then multiple remainders with 11 the total remainder is 55 so 9999-55=9944 is the answer.

9999/8*11=99/8=5*11=55.
9999-55=9944.
Post your comments here:

Your comments will be displayed after verification.

Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers