Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 8)
8.
The largest 4 digit number exactly divisible by 88 is:
9944
9768
9988
8888
None of these
Answer: Option
Explanation:
Largest 4-digit number = 9999

 88) 9999 (113
     88
     ----
     119
      88
     ----
      319
      264
      ---
       55
      ---
       
 Required number = (9999 - 55)
                 = 9944.        
Discussion:
67 comments Page 1 of 7.

Sudeshna said:   7 years ago
@Biswarup rout.

A. 4 digit number has Th H T and One's place.
Under each place value, the minimum value we can write is 0 and the maximum value is 9. Hence, if ones, tens, hundred and Thousand all have 9, then 9999 is the largest 4 digit number.

Similarly, largest 5 digits will have 99999 so on and so forth.

The smallest 4 digit will be 1000.
Smallest 5 digit will be 10000.

Abhishek kumar said:   8 years ago
It is one of the best ways to solve this type of questions that you take4 digit largest number 9999.

Then divide it by 88 but brake 88 in 8*11 then divide 9999 by 11 you will get 99.

Then you will divide it by 8 you will get 5 as remainder then multiple remainders with 11 the total remainder is 55 so 9999-55=9944 is the answer.

9999/8*11=99/8=5*11=55.
9999-55=9944.

Saravanan said:   1 decade ago
Another simple method.

Divide the largest number by the given number.i.e 9999/88 which is equal to 113.625

Now multiply the exact number (number before the .(dot) i.e 625 (113*88). The result would be 9944.

Also we are taking 9999 because the largest number from 01 to 1000 (the numbers given are between 01 to 1000) is 9999.

Sitam said:   1 decade ago
To akansha it is a correct method.formula of divisible by 11 is odd place no=even place number and by 8 is the sum of first 3 digit must be divisible by 8.Here greatest number is given 9944 which fulfil the two condition above.Although others are also fulfil the conditions but they are not greatest.

Darshan Prajapati said:   4 years ago
How it is correct? because above in the example no. 6 method is to split the number & then check the number either diveded by all or not.

And same method if we applied in this example (11*2*4) = 88.

So, 9988 is divided by all 11, 2, & 4.

Please anyone clarify this.
(3)

Darshan Prajapati said:   4 years ago
How it is correct? because above in the example no. 6 method is to split the number & then check the number either diveded by all or not.

And same method if we applied in this example (11*2*4) = 88.

So, 9988 is divided by all 11, 2, & 4.

Please anyone clarify this.
(6)

Murali goud said:   7 years ago
We can write 88=11*8=11*4*2.

So the 4 digit number must be divisible by all the digits i.e 11,4,2.

But where am I confusing is the number 9988 is divisible by all the numbers i.e 11,4,2 but it is not divisible by 88.

Why? The method is wrong or write? Can anyone suggest?
(2)

Reshma said:   4 years ago
9944/88 = 113.
9768/88 = 111.
9988/88 = 113.05,
8888/88 = 101.

So, thecorrect answer is option C.
(7)

Goutham said:   1 decade ago
The largest 4-digit no. is 9999. when we divide it by 88 we got remainder as 55. It means that 9999 is 55 more than a number that is completely divisible by 88. So we have to subtract that extent 55 from 9999 to get actual number.

Ruchita said:   6 years ago
Here is an easier method.

First, divide 9999 by 11(9999/11=909).
Then divide 909 by 8 (909/8 = we get 5 reminder).

But 5 is for 909.
909=5.
9999=?.
Then 9099*5/909.

We can get 55 reminder by this easy method.


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