Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 3)

Numbers

It is being given that (2³² + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?

(2¹⁶ + 1)

(2¹⁶ - 1)

(7 x 2²³)

(2⁹⁶ + 1)

Answer: Option

Explanation:

Let 2³² = x. Then, (2³² + 1) = (x + 1).

Let (x + 1) be completely divisible by the natural number N. Then,

(2⁹⁶ + 1) = [(2³²)³ + 1] = (x³ + 1) = (x + 1)(x² - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.

Discussion:

137 comments Page 12 of 14.

Deepa said: 1 decade ago

How can we know (x^3+1) is divisible by n?

Ashwini said: 1 decade ago

I can't understand please explain briefly?

Kapis said: 10 years ago

Please give me a basic and simple methods.

Varun said: 10 years ago

I am not understand. Please explain again.

Manohar said: 1 decade ago

I cannot understand please explain again.

Harshita said: 1 decade ago

I can't understand. Please explain again.

Abarna said: 6 years ago

I can't understand it, please explain me.

Arun said: 1 decade ago

I understand but I want another example.

Radhika said: 10 years ago

I can't understand please again reply.

Sravanthi said: 9 years ago

I can't understand. Please explain it.

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