Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 3)
3.
It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Answer: Option
Explanation:
Let 232 = x. Then, (232 + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
Discussion:
137 comments Page 13 of 14.
Anuj yadav said:
5 years ago
I think the formula will be 2^(n.3)+1.
Sonu said:
6 years ago
Your explanation is very complicated.
Pavi said:
2 decades ago
I cannot understand, please explain.
Nani said:
1 decade ago
Why we don't consider (x^2 - x + 1)?
Supriya Pawar said:
7 years ago
96/3 = 32 so the divisible no is 3.
Dilip said:
5 years ago
I'm not understanding this problem.
(1)
Karthik said:
1 decade ago
How do u directly write (2^96+1) ?
Richa said:
1 decade ago
Unable to undestand. Kindly help.
Rajan said:
1 decade ago
Please explain briefly this sum.
Anusha said:
1 decade ago
Is there any simple procedure?
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