Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 3)
3.
It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Answer: Option
Explanation:
Let 232 = x. Then, (232 + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
Discussion:
137 comments Page 14 of 14.
Madhu said:
9 years ago
How you take 2^96 +1 exactly?
Manoj said:
1 decade ago
I can't understand. Explain.
Anomie said:
2 months ago
Thanks for the explanation.
(2)
Pranshu said:
9 years ago
Why not option A? Explain.
Savitri said:
9 years ago
How to solve 2^64, 3^432?
Divyarekha said:
1 decade ago
Very good explanation.
Ram said:
1 decade ago
I can't understand.
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