Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 3)
3.
It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Answer: Option
Explanation:
Let 232 = x. Then, (232 + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
Discussion:
137 comments Page 11 of 14.
Octavia said:
5 years ago
I don't understand. Please explain in detail.
Rahul wadhwa said:
1 decade ago
Really its very confusing!!!!!!!!!!!!!!!!!!!
Rayanna said:
9 years ago
I can't understand please explain me easily.
Shirisha said:
9 years ago
I understand this. But I want simple method.
Kannan said:
7 years ago
Here, 2^96 / 2^32 = 0 is completely divided.
VENKY said:
3 years ago
I can't understand, anyone can explain this?
(60)
Donbabu said:
1 year ago
I can't understand, anyone can explain this?
(9)
Mala said:
1 decade ago
Its confusing. Is there any simple methods?
Lekha said:
1 decade ago
I can't understand. Please explain again. !
Nayudu said:
6 years ago
Agree @Diya.
Can anyone please explain it?
Can anyone please explain it?
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