Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 3)
3.
It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Answer: Option
Explanation:
Let 232 = x. Then, (232 + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
Discussion:
137 comments Page 10 of 14.
Saad said:
6 years ago
I can't understand. Please, anyone, explain it briefly.
Shyam Ingalagi said:
2 months ago
What is the exponentiation rule? Please explain to me.
Siprarani tripathy said:
9 years ago
Dear sir, I can't understand. Kindly explain clearly.
Sajal said:
9 years ago
I didn't understand the last step. Please explain it.
Aryan Verma said:
1 decade ago
@Nagaraj Your Way of making understand is good dear.
Vaithi said:
10 years ago
I am not clear about the answer. Please help me.
Saruu said:
9 years ago
Can anyone give a simple method to explain this?
Jitendra said:
1 decade ago
Please help in another example similar to this.
Sajid said:
9 years ago
I don't understand. Please, someone explain me.
Karthi said:
1 decade ago
Give some explanations to understand clearly.
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