Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 43)
43.
Which one of the following is the common factor of (4743 + 4343) and (4747 + 4347) ?
Answer: Option
Explanation:
When n is odd, (xn + an) is always divisible by (x + a).
Each one of (4743 + 4343) and (4747 + 4347) is divisible by (47 + 43).
Discussion:
17 comments Page 1 of 2.
Arulprakash said:
1 decade ago
What is meant by common factor? can anyone explain?
Vamsi Krishna said:
1 decade ago
When n is odd, (xn + an) is always divisible by (x + a).
Then when n is even , what will be the result??
Then when n is even , what will be the result??
Pratibha said:
1 decade ago
What if the number is even?
Madhu said:
1 decade ago
How we solve when it will be an even number?
Anil said:
1 decade ago
a^n - b^n is divisible by a+b when n is even.
Sumitjain said:
1 decade ago
@Anil. can you explain nicely?
Prakash sahani said:
10 years ago
Any one kindly described in detail, detail and logically? Please.
Akshay said:
10 years ago
When the HCF of two no. is 1, this no. is called common factor.
Ex. 72 = 8*9.
8 = 2^3.
9 = 3^2.
The HCF of 8 & 9 is 1. Hence it makes as common factor.
Ex. 72 = 8*9.
8 = 2^3.
9 = 3^2.
The HCF of 8 & 9 is 1. Hence it makes as common factor.
Naimul said:
9 years ago
(47^43 + 43^43).
= 43^43 (4^43 + 1^43).
Again,
43^47 (4^47 + 1^47).
So, 43^43 * 43^47.
= 43 (43 + 47).
= 43^43 (4^43 + 1^43).
Again,
43^47 (4^47 + 1^47).
So, 43^43 * 43^47.
= 43 (43 + 47).
Sasikumar said:
9 years ago
Can anyone explain it please?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers