Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 43)
43.
Which one of the following is the common factor of (4743 + 4343) and (4747 + 4347) ?
Answer: Option
Explanation:
When n is odd, (xn + an) is always divisible by (x + a).
Each one of (4743 + 4343) and (4747 + 4347) is divisible by (47 + 43).
Discussion:
17 comments Page 2 of 2.
Simran said:
9 years ago
Can be solved by cyclicity.
Unit place of 1st number is 0 after addition. Which means it is a factor of 10. Out of options only 43 + 47 = 90 is the factor of 10. So, 43 + 47 is the answer.
Unit place of 1st number is 0 after addition. Which means it is a factor of 10. Out of options only 43 + 47 = 90 is the factor of 10. So, 43 + 47 is the answer.
(2)
Ravi kant said:
9 years ago
When power n is odd then (a+b) divide a^n+b^n.
eg: a^3 + b^3 = (a + b)(a^2 - ab + b^2).
And, if power n is even then it divide a^n-b^n.
eg: a^3 - b^3) = (a - b)(a^2 + ab + b^2).
eg: a^3 + b^3 = (a + b)(a^2 - ab + b^2).
And, if power n is even then it divide a^n-b^n.
eg: a^3 - b^3) = (a - b)(a^2 + ab + b^2).
(2)
Suyog said:
8 years ago
A number which divides two or more number is called common factor of that number.
Navneet said:
7 years ago
Can anyone please explain it, what if the value of n is even? Then what will be the common factor?
(3)
Praveen said:
5 years ago
How to divide it? Please explain in detail.
(1)
Vijaybarath said:
4 years ago
Simply;
a3 + b3 = (a+b) (a2+b2-ab) is odd, i.e we can dived by a+b.
Whereas, if even a3-b3 formula i.e divide by a-b.
a3 + b3 = (a+b) (a2+b2-ab) is odd, i.e we can dived by a+b.
Whereas, if even a3-b3 formula i.e divide by a-b.
Maneesh said:
4 years ago
a^3 + b^3 = (a+b) (a2+b2-ab) is odd and we have to plus, i.e. we can divide by a+b.
Whereas, if n is odd and we have minus, a3-b3 formula i.e divide by a-b.
Whereas, if n is odd and we have minus, a3-b3 formula i.e divide by a-b.
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