Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 78)
78.
What will be remainder when 17200 is divided by 18 ?
Answer: Option
Explanation:
When n is even. (xn - an) is completely divisibly by (x + a)
(17200 - 1200) is completely divisible by (17 + 1), i.e., 18.
(17200 - 1) is completely divisible by 18.
On dividing 17200 by 18, we get 1 as remainder.
Discussion:
27 comments Page 2 of 3.
Siddeswara Reddy said:
1 decade ago
When (X-1)^n is divided by X then R=1, If n is even natural number and if n is odd natural number then R = X-1.
Kaveri said:
5 years ago
When 17^200 is completely divisible by 18 then the remainder needs to be 0 right, then how come 1?
Ravikumar Chauhan said:
6 years ago
But from where 1^200 come?
17^200 is same or has the same value 17^200-1^200.
Please explain.
17^200 is same or has the same value 17^200-1^200.
Please explain.
(1)
Bharath said:
9 years ago
17^200 = (18 - 1)^200 gives (18^200) - 2 * 18 + 1 which give remainder 1 when divided by 18.
Manoranjan sahoo said:
7 years ago
(17^199+17)/18,
(17^199+1)/18 is completely divisible,
and the reminder is 16.
(17^199+1)/18 is completely divisible,
and the reminder is 16.
Samridhi shah said:
3 years ago
What if the power was odd no, for ex 17 power 137?
How to solve that?
How to solve that?
(2)
Gururaj said:
1 decade ago
Simple way way is:
17 ^2 %18 =1.
(17^2)*(7^100) %18 will also be 1.
17 ^2 %18 =1.
(17^2)*(7^100) %18 will also be 1.
Akhil said:
1 decade ago
Why cant it be (17^200-2^200) is completely divisible by 17+2=19 ?
Shubham said:
8 years ago
Can somebody give all the division rules for term (x^n - a^n).
Gaurav said:
10 years ago
11/3 reminder is 2 but what is -1(11-12)? Please explain more.
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